2 years ago

Please help with math assignment

Mathematics

1 answer:

soldier1979 [14.2K]2 years ago

4 0

Answer:

a = 4√2, h = 2√3

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Look at the two equations:

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Step-by-step explanation:

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Sin theta = 1/4, tan theta > 0<br> Find cos theta/2

lozanna [386]

Answer:

Step-by-step explanation:

sin θ=1/4,tan θ>0

so θ lies in first quadrant.

cos θ=√(1-sin²θ)=√(1-(1/4)²)=√(1-1/16)=√(15/16)=√15/4

$2cos^2 \frac{\theta}{2} =1+cos \theta$

$2~cos^2\frac{\theta}{2} =1+\frac{\sqrt{15} }{4} =\frac{4+\sqrt{15}}{4} \\cos~\frac{\theta}{2} =\sqrt{\frac{4+\sqrt{15} }{4 \times 2} } \\cos\frac{\theta}{2} =\frac{\sqrt{8+2\sqrt{15}} }{4}$

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1 year ago