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gtnhenbr [62]
3 years ago
13

Plz help me with this Im timed will mark as brainliest

Mathematics
2 answers:
viktelen [127]3 years ago
4 0
Well what i got was 79.3 by finding the average by adding it all together then divided it by how many numbers
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

It seems like John is trying to find the mean, or average.

Green is 82

blue is 320

red is 4

Step-by-step explanation:

82 is the score John must get to have the average of 80

320 is the number you must divide by 4 to get 80

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I need to simplify this
Korvikt [17]
Hi there!

3 \sqrt{54} + 2 \sqrt{24} =
First we split up the square root into two parts.

3 \times \sqrt{9} \times \sqrt{6} + 2 \times \sqrt{4} \times \sqrt{6} =
Now we calculate the value of the square roots which have an integer as a solution

3 \times 3 \times \sqrt{6} + 2 \times 2 \times \sqrt{6} =
Multiplying the integers gives us our next step.

9 \sqrt{6} + 4 \sqrt{6} =
And finally we add up the roots.

13 \sqrt{6}
3 0
3 years ago
The formula v = ir shows the relationship between voltage, current, and resistance. solve this formula for r.
Artemon [7]
It would be A do you need me to explain?

3 0
3 years ago
I need answer on this graphing va substitution.Problem 7 I tried to solve it but not sure that’s correct
Bond [772]

Given the system of equations:

\begin{gathered} 2x+9y=27 \\ x-3y=-24 \end{gathered}

To solve it by substitution, follow the steps below.

Step 1: Solve one linear equation for x in terms of y.

Let's choose the second equation. To solve it for x, add 3y to each side of the equations.

\begin{gathered} x-3y=-24 \\ x-3y+3y=-24+3y \\ x=-24+3y \end{gathered}

Step 2: Substitute the expression found for x in the first equation.

\begin{gathered} 2x+9y=27 \\ 2\cdot(-24+3y)+9y=27 \\ -48+6y+9y=27 \\ -48+15y=27 \end{gathered}

Step 3: Isolate y in the equation found in step 2.

To do it, first, add 48 to both sides.

\begin{gathered} -48+15y=27 \\ -48+15y+48=27+48 \\ 15y=75 \end{gathered}

Then, divide both sides by 15.

\begin{gathered} \frac{15y}{15}=\frac{75}{15} \\ y=5 \end{gathered}

Step 4: Substitute y by 5 in the relation found in step 1 to find x.

\begin{gathered} x=-24+3y \\ x=-24+3\cdot5 \\ x=-24+15 \\ x=-9 \end{gathered}

Answer:

x = -9

y = 5

or (-9, 5)

Also, you can graph the lines by choosing two points from each equation, according to the picture below.

7 0
1 year ago
Given: <PQR is a right angle Prove: <PQS and <SQR are complemantary​
amm1812

Answer:

see the explanation

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠PQS+m∠SQR=m∠PQR ----> equation A (by Addition Angle Postulate)

we have that

m∠PQR=90° ----> equation B given problem (because is a right angle)

substitute equation B in equation A

m∠PQS+m∠SQR=90°

Remember that

Two angles re complementary is their sum is equal to 90 degrees (Definition of complementary angles)

therefore

m∠PQS and m∠SQR are complementary angles

3 0
3 years ago
How do I solve: 6x^2 -x-12=0 ^2 means squared by the way!
Alchen [17]
6x^2 -x-12=0\\
6x^2+8x-9x-12=0\\
2x(3x+4)-3(3x+4)=0\\
(2x-3)(3x+4)=0\\
x=\frac{3}{2} \vee x=-\frac{4}{3}

7 0
3 years ago
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