Answer:
The approximate probability that more than 360 of these people will be against increasing taxes is P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
The right answer is B.
Step-by-step explanation:
According to the given data we have the following:
sample size, h=600
probability against increase tax p=0.45
The probability that in a sample of 600 people, more that 360 people will be against increasing taxes.
We find that P(P>360/600)=P(P>0.6)
The sample proposition of p is approximately normally distributed mith mean p=0.45
standard deviation σ=√P(1-P)/n=√0.45(1-0.45)/600
If x≅N(u,σ∧∧-2), then z=(x-u)/σ≅N(0,1)
Now, P(P>0.6)=P(<u>P-P</u> > <u>0.6-0.45)</u>
σ √0.45*0.55/600
=P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
His mistake is he didn't make 6/10 to 60/100 he added them without changing the 6/10
1. discriminant = b^2 - 4ac = (-5)^2 - (4 x 1 x 7) = 25 - 28 = -3 [imaginary root]
2. discriminant = (-5)^2 - (4 x 1 x -4) = 25 - (-16) = 25 + 16 = 41 [real and irrational root]
3. discriminant = (8)^2 - (4 x 16 x 1) = 64 - 64 = 0 [double root]
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hope it helps
Slope = (y2 - y1)/(x2 - x1) = (10 - 70)/(5 - (-15)) = -60/(5 + 15) = -60/20 = -3
