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3 years ago

14

Which statement best describes the area of Triangle ABC shown below?

1 answer:

melamori03 [73]3 years ago

5 0

Answer: It is one-half the area of a rectangle with sides 2 units × 3 units.

It is twice the area of a square of side length 3 units.

It is one-half the area of a square of side length 3 units.

Step-by-step explanation:

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assume the age of night school students is normally distributed. A simple random sample of 24 night school students had an avera

aleksley [76]

Let
n = number of data
s = standard deviation (sample)
S = standard deviation (population)

The working equations is

$\frac{(n-1) s^{2} }{ x^{2}_{right} } \ \textless \ S^{2} \ \textless \ \frac{(n-1) s^{2} }{ x^{2}_{left} }$

To find $x^{2}_{right}$ , : (1 - 0.90)/2 = 0.05

To find $x^{2}_{left}$ , : 1 - 0.05 = 0.95

Degrees of freedom = n-1 = 24 - 1 = 23

This is shown in the figure attached. Since there is no row for df=23, we interpolate. Thus,

$x^{2}_{left} = 13.093$

$x^{2}_{right} = 35.17$

Substitute all values,

$\frac{(24-1) 5.6^{2} }{ 35.17} \ \textless \ S^{2} \ \textless \ \frac{(24-1) 5.6^{2} }{ 13.093} }$

Thus the answer is,

$20.51\ \textless \ S^{2} \ \textless \ 55.09$

5 0

3 years ago

Please help! this is an overdue assignment and i can get through this one. I WILL MARK BRAINLIEST WHOEVER ANSWERS FIRST AMD CORR

Daniel [21]

Answer:

Step-by-step explanation:

The skier would have to go skiing 15 days im pretty sure.

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7 0

3 years ago

Simplify the sum 4/m+9+5/m^2-81

Y_Kistochka [10]

4/(m+9)+5/(m^2-81)=
4/ ( m+9) +5 / ( m-9)(m+9)=
4(m-9)/(m+9)(m-9)+ 5 / (m+9)(m-9)=
(4m-36+5)/(m+9)(m-9)=
4m-31/ (m+9)(m-9)

the answer is D

7 0

3 years ago

Read 2 more answers

The given graph represents the function f(x) = 2(5)*x

Sauron [17]

Answer:

f(x) = 2(5)*x

y=(2)(5)x

Y=10x

Step-by-step explanation: is this steps help you

6 0

3 years ago

8. The endpoints of ST are s(-3, 2) and t(5,8). Find the coordinates of the midpoint of ST. Then find ST. OA midpoint: (1,5); ST

Naya [18.7K]

Answer:

The mid point of ST is (1,5) and ST = 10 units

Step-by-step explanation:

It is given that,

S(-3,2) and T(5,8). We need to find the coordinates of the midpoint of ST and also ST.

Let (x,y) be the mid point of ST. Using mid-point formula we get :

$(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})$

We have, x₁ = -3, x₂ = 5, y₁ = 2 and y₂ = 8

So,

$(x,y)=(\dfrac{-3+5}{2},\dfrac{2+8}{2})\\\\(x,y)=(1,5)$

(1,5) is the midpoint of ST.

Using distance formula to find ST as follows :

$ST=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\ST=\sqrt{(5-(-3))^2+(8-2)^2} \\\\ST=10\ \text{units}$

Hence, the mid point of ST is (1,5) and ST = 10 units.

7 0

3 years ago