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Yakvenalex [24]

3 years ago

6

A block of wood measures 4.5 inches by 3.5 inches by 7 inches.what is the volume of the block of wood

1 answer:

Ira Lisetskai [31]3 years ago

3 0

The volume is the height times the lenght times the width (order does not matter in this case).

4.5 x 3.5 x 7= 110.25

The volume of this block of wood is 110 inches.

PLEASE, PLEASE, PLEASE, PLEASE PICK ME AS BRAINLIEST!!!!! PLEASE!!!!

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Find all vertical and horizontal asymptotes of the graph of the function. (Enter your answers as a comma-separated list.)

Vladimir79 [104]

Hello,

y=(1+x)/(1-x)

y=-1
Asymptote horizontal $\lim_{n \to \infty} \frac{1+x}{1-x} =-1$

x=1
Asymptote vertical $\lim_{x \to 1} \frac{1+x}{1-x}=\infty$

3 0

3 years ago

Write an equation of a line in slope-intercept form that passes through the point (8, 9) and has a slope of 3.

Komok [63]

Answer:

y=3x-15

Step-by-step explanation:

y-y1=m(x-x1)

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y=3x-24+9

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2 years ago

A polygon will be dilated on a coordinate grid to create a smaller polygon. The polygon is dilated usi X

Reika [66]

Answer:

D). (x, y) --> (0.9x, 0.9y).

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6 0

3 years ago

Someone help me please

Masteriza [31]

Answer:

$(5,1)$

Step-by-step explanation:

Hi there!

Midpoint = $\displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$ where the two endpoints are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given information:

Midpoint = (5,3), Endpoint = (5,5)

$(5,3)=\displaystyle (\frac{5+x_2}{2},\frac{5+y_2}{2} )$ where $(x_2,y_2)$ is the other endpoint

Solve for $x_2$ :

$\displaystyle \frac{5+x_2}{2} =5\\\\5+x_2 =10\\x_2 =5$

Solve for $y_2$ :

$\displaystyle\frac{5+y_2}{2}=3 \\\\{5+y_2}=6\\y_2=1$

Therefore, the other endpoint $(x_2,y_2)$ is $(5,1)$ .

I hope this helps!

4 0

3 years ago

Read 2 more answers

In April, the Messa family gets 800 text messages included in their plan. Together, Tommy and Mary use half of the messages. Jac

laiz [17]

Answer: See explanation

Step-by-step explanation:

Total number of text messages = 800

Amount used by Tommy and Mary = 1/2 × 800 = 400

Number of messages uses by Jack and Stefanie = 240

The expression to find the number of messages Cathy uses will be:

= 800 - (1/2 × 800) - 240

Since the expression is 800 - (1/2 × 800) - 240, the number of messages that Cathy will use will be:

= 800 - (1/2 × 800) - 240

= 800 - 400 - 240

= 160 messages

3 0

3 years ago