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trasher [3.6K]
2 years ago
6

You have come in contact with the Zombie Virus and are now infected with one strand. The

Mathematics
1 answer:
coldgirl [10]2 years ago
5 0

Answer:

y=2^x

Step-by-step explanation:

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Solve:<br> a.) 5(x - 2) &gt; -15<br> AND<br> b.) x/1 - 9 &lt; -10
uysha [10]

Answer:

a.) x>-1

b.) x/1 - 9 < -10

Step-by-step explanation:

a.)

5(x - 2) > -15

(divide both sides)

x-2>-3

(move the constant to the right)

x>-3+2

(calculate)

x>-1

(answer)

b.)

x/1 - 9 < -10

(divide)

x-9<-10

(move the constant to the right)

x<-10+9

(calculate)

x/1 - 9 < -10

(answer)

6 0
3 years ago
How much greater is 6/7 then 5/14
iVinArrow [24]
12/14 more then 5/14 in 2.4 times

7 0
3 years ago
(06.04 MC)
Andru [333]

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

◉ \large\bm{ -4}

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

Before performing any calculation it's good to recall a few properties of integrals:

\small\longrightarrow \sf{\int_{a}^b(nf(x) + m)dx = n \int^b _{a}f(x)dx +  \int_{a}^bmdx}

\small\sf{\longrightarrow If \: a \angle c \angle b \Longrightarrow \int^{b} _a  f(x)dx= \int^c _a f(x)dx+  \int^{b} _c  f(x)dx }

So we apply the first property in the first expression given by the question:

\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}

And we solve the second integral:

\small\sf{\longrightarrow2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot(3 - ( - 2)) }

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} 2dx  = 2 \int ^3_{-2} f(x)dx +   2 \cdot5 = 2 \int^3_{-2} f(x)dx10 = }

Then we take the last equation and we subtract 10 from both sides:

\sf{{\longrightarrow 2 \int ^3_{-2} f(x)dx} + 10 - 10 = 18 - 10}

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx  = 8}

And we divide both sides by 2:

\small\longrightarrow \sf{\dfrac{2  {  \int}^{3} _{2}  }{2}  =  \dfrac{8}{2} }

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx=4}

Then we apply the second property to this integral:

\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 4}

Then we use the other equality in the question and we get:

\small\sf{\longrightarrow 2 \int ^3_{-2} f(x)dx  =  2 \int ^3_{-2} f(x)dx  = 8 +  2 \int ^3_{-2} f(x)dx  = 4}

\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =4}

We substract 8 from both sides:

\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx -8=4}

• \small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =-4}

7 0
2 years ago
In the expression -5g12 whIn the expression -5g12 which part is the coefficient?ich part is the base?
kiruha [24]

Answer:

The coefficient is -5, and the base is 12.

Step-by-step explanation:

The coefficient is the number that the variable is being multiplied by in an expression, so -5 would be the coefficient in the expression -5g_{12}. The base would be the little subscript number that is next to the variable, so the base in the expression -5g_{12} is 12.

6 0
3 years ago
Can someone help me please!!?? Eleven and seven-hundredths added to four and twenty-five hundredth the sum is
zloy xaker [14]

Answer:

15.32

Step-by-step explanation:

Eleven and seven-hundredths =11+\frac{7}{100}

(Here, \frac{1}{100} denotes the hundredth)

Four and twenty-five hundredth =4+\frac{25}{100}

Therefore,

Sum of Eleven and seven-hundredths added to four and twenty-five hundredth = 11+\frac{7}{100}+4+\frac{25}{100}

=15+\frac{32}{100}

=15+0.32

=15.32

8 0
3 years ago
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