Answer:
Answer: First, we use Ohm's law ( V = I × R ), to find the current through the resistor. The voltage across the resistor is V = 9 V. The resistance of the resistor is R = 100 Ω. Then, we can use the power rule ( P = I × V ), to find the power dissipated by the resistor
Step-by-step explanation:
i dont know if its the right answer but here
Answer:
Step-by-step explanation:
4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.
b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.
c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.
d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.
e). If a parallelogram has four congruent sides, then it must be a SQUARE.
5). Given quadrilateral SELF is a rhombus.
a). All sides of a rhombus are equal,
Therefore, ES = EL = 25
b). Diagonals of a rhombus bisects the opposite angles,
Therefore, m∠ELS = m∠FLS
3x - 2 = 2x + 7
3x - 2x = 7 + 2
x = 9
c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.
m∠ELF = 2(m∠ELS) = 2(2y - 9)
m∠LES = 2(m∠LEF) = 2(3y + 9)
And 2(2y - 9) + 2(3y + 9) = 180
(2y - 9) + (3y + 9) = 90
5y = 90
y = 18
5.
First plug the value of x into the equation
then solve for y
6. Do the same steps
Ok, so we know one point is (4,2) and the other is (-4, 0)
Slope: -2/-8 = 1/4
y ? 1/4x + b
0 = -1 + b
b = 1
y < 1/4x + 1
Answer:
3 11/20
Step-by-step explanation:
Total gallons of water=7
Spring water=two and one-fourth gallon=2 1/4
Filtered water=one and one-fifth
=1 1/5
Spring water+filtered water=2 1/4 + 1 1/5
=9/4+6/5
= 45+24/20
=69/20
=3 9/20
How many gallons of water were not spring or filtered
=Total gallons- (spring+ filtered water)
=7-69/20
=140-69/20
=71/20
=3 11/20
