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nalin [4]
3 years ago
15

Help again 14 more questions

Mathematics
1 answer:
MArishka [77]3 years ago
5 0

Answer:

A certain element has 25 protons.

Step-by-step explanation:

Please mark brainliest

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Nata [24]
Don’t stress. try taking a nap. or watching a movie. Or listen to calming music.
4 0
3 years ago
Read 2 more answers
What is the vertex and intercepts for y=(5x-2)(2x+3)
Sophie [7]

Answer:

vertex = (-\frac{11}{20} ,-\frac{361}{40} )

Intercepts for x = (\frac{2}{5} ,0), (-\frac{2}{5} ,0)

intercepts for y = (0,-6)

4 0
3 years ago
The figure à shown on ancient coin which was once used in china.the coin is in the shape of a circle of radius 3cm with a square
lianna [129]

Answer:

(1) 2π - x² = 0 (2) x = 2.5 cm (3) perimeter = 10 cm

Step-by-step explanation:

(1)The area of the circular coin without the inner square removed is πr² where r = 3 cm is the radius of the coin. So, the area of the coin without the inner square removed is πr² = π(3 cm)² = 9π cm²

The area of the square of x sides removed from its center is x².

The area A of the each face of the coin is thus A = 9π - x²

Since the area of each face of the coin A = 7π cm²,

then

7π = 9π - x²

9π - 7π - x² = 0

2π - x² = 0

(2) Solve the equation 2π - x² = 0

2π - x² = 0

x² = 2π

x = ±√(2π)

x = ± 2.51 cm

Since x cannot be negative, we take the positive answer.

So, x = 2.51 cm

≅ 2.5 cm

(3) Find the perimeter of the square

The perimeter of the square, p is given by p = 4x

p = 4 × 2.51 cm

= 10.04 cm

≅ 10 cm

8 0
3 years ago
What is the slope (2,6) (-1, -5)
egoroff_w [7]
answer is 11/3.

HOPE THIS HELPS
mark me brainleist pls
8 0
3 years ago
I cannot solve this. I don't know how.
Pani-rosa [81]
<h3>Answer:</h3>
  • f(q) = q² -2q +3
  • f(x+h) = (x+h)² -2(x+h) +3
  • (f(x+h) -f(x))/h = 2x -2 +h
<h3>Step-by-step explanation:</h3>

The notation f(x) means you have a function that has been given the name f, and it makes use of the variable x. The variable in the parentheses is called the "argument" of the function f.

(a) To find f(q), you put q everywhere x is in the function equation. This is called evaluating the function for an argument of "q". In the following, note that we have simply changed x to q. (It's really that simple.)

... f(q) = q² -2q +3

(b) As in the previous case, we replace x with (x+h) everywhere.

... f(x+h) = (x+h)² -2(x+h) +3

You can multiply it out, but there appears to be no need to do so for this part of the question.

(c) The intent here is that f(x+h) and f(x) will be replaced by their values and the whole thing simplified. This requires you  expand the expression you see in part (b), subtract f(x), collect terms, and divide the whole thing by h. You have to make use of what you know about multiplying binomials.

We can do it in parts:

... f(x+h) = (x+h)² -2(x+h) +3

... = (x² +2xh +h²) + (-2x -2h) +3

Separating the h terms, this looks like ...

... = (x² -2x +3) + (2xh -2h +h²)

Now, we can finish the numerator part of the expression by subtracting f(x):

... f(x+h) -f(x) = (x² -2x +3) +(2xh -2h +h²) -(x² -2x +3)

You can see that the stuff in the first parentheses matches that in the last parentheses, so when we subtract the latter from the former, we get zero. We are left with only the terms containing h.

... f(x+h) -f(x) = 2xh -2h +h²

To finish up this problem, we need to divide this numerator value by the denominator h.

... (f(x+h) -f(x))/h = (2xh -2h +h²)/h

... = (2xh)/h -(2h)/h +h²/h

... = 2x -2 +h . . . . . this is the value of the expression

... (f(x+h) -f(x))/h = 2x -2 +h

4 0
3 years ago
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