The z-score is given by the formula:
z=(x-μ)/σ
μ=1252
σ=129
The answer to the questions given will be as follows:
a] <span>what is the probability that a randomly selected bag contains between 1100 and 1400 chocolate chips?
z=(1400-1252)/129
z=1.15625
P(x</span>≤<span>1400)=0.8770
z=(1100-1252)/129
z=0.1190
P(X</span>≤1100<span>)=0.1190
the answer will be:
P(1100</span>≤x≤1400<span>)=0.8770-0.1190=0.758
b]</span><span>what is the probability that a randomly selected bag contains fewer than 1000 chocolate chips?
</span>z=(1000-1252)/129=-1.954
P(X≤1000)=0.0256
c] <span>what proportion of bags contains more than 1200 chocolate chips?
z=(1200-1252)/129
z=-0.4031
P(X</span>≥1200<span>)=1-P(X</span>≤1200<span>)=1-0.4031=0.5969
</span>
Answer:
I believe your answer is going to be roughly 767.8 which if you need to use fractions would be 767 4/5.
Step-by-step explanation:
Hope this helped in some way
These are the two equation
10-2
13-5
Your answer is angle JCL.
Angle JCL+Angle LCT = 90°
