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BigorU [14]
3 years ago
12

The radius of star A is 6.9203x10^5 km, which is 108.7 times the rafius of star B. what is the radius of the star B?

Mathematics
1 answer:
Kay [80]3 years ago
7 0

Answer:

6366.4213

Step-by-step explanation: 6.9203x10^5 is 692,030. I divided 692,030 by 108.7 to get the answer. Anybody can correct any error I may have.

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What is the distance between -6 and -3 on a number line?
Ira Lisetskai [31]
I think it's 3 but idk I'm not good at math
7 0
3 years ago
Read 2 more answers
GIVEN: f(x)=3x-7, g(x)=2x^(2)-3x+1, h(x)=4x+1, k(x)=-x^(2)+3
tekilochka [14]

Answer:

32x^2+4x

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3 0
3 years ago
The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped
kakasveta [241]

Check the picture below.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2  = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0
3 years ago
How do you graph y= -5
olchik [2.2K]
Since y=k, there is a slope of zero, which is just a horizontal line k units from the x-axis.  In this case k=-5, so the graph of y=-5 is a horizontal line 5 units below the x-axis...
7 0
3 years ago
Xm-2m if x=-2 and m=-3
swat32
The answer would be 12. (-2)(-3) = 6, then (2)(-3) is -6. 6-(-6) would be 6+6.
3 0
3 years ago
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