I need the answer to this please.

When signing up for a new checking account you answer "No" and opt out of overdraft protection. On this day, you have $10 in you

Rus_ich [418]

Answer:

You may likely be charged an Overdraft fee or amount on each of the transactions carried out by you and you will have to repay the bank the overdrawn amount.

Step-by-step explanation:

Based on the information given we were told that you opt out of an overdraft protection which means that in a situation were you have the amount of $10 in your bank account in which you carried out some transactions with your debit card such as buying lunch for the amount of $12, movie ticket for the amount of $12 and as well dinner for the amount of $15 the end result is that their is likelihood of you to be charged an overdraft fee or an overdraft amount on each of the transaction carried out by you and secondly you will also need to repay or pay back the bank for the amount of money overdrawn which is $29 calculated as :

Amount overdrawn =[($12+$12+$15)-$10]

Amount overdrawn=$39-$10

Amount overdrawn =$29

4 0

3 years ago

A test driver has to drive a car on a 1-mile track for two rounds in a way, that his average speed is 60 mph. On his first round

Darya [45]

(40+x)/2=60

40 +x = 120

x = 80

check :

40+80 = 120

120/2 = 60

so his second round needs to be 80 mph

3 0

3 years ago

Where do I put parentheses and brackets to make the equation 40-2*8+2-10 = 10?

xenn [34]

I think it would go like this:[40- 2 (8+2)]=10 I think

8 0

3 years ago

How do you factor: 2x + -15

Arisa [49]

Answer:

It is not factorable.

Step-by-step explanation:

It is not factorable with rational numbers.

6 0

3 years ago

Read 2 more answers

The American Association of Individual Investors conducts a weekly survey of its members to measure the percent who are bullish,

vredina [299]

Answer:

1. There is not enough evidence to support the claim that bullish sentiment differs from its long-term average of 0.39.

2. There is enough evidence to support the claim that bearish sentiment is above its long-term average of 0.30.

Step-by-step explanation:

The question is incomplete:

The American Association of Individual Investors conducts a weekly survey of its members to measure the percent who are bullish, bearish, and neutral on the stock market for the next six months. For the week ending November 7, 2012 the survey results showed 38.5% bullish, 21.6% neutral, and 39.9% bearish (AAII website, November 12, 2012). Assume these results are based on a sample of 300 AAII members.

1. This is a hypothesis test for a proportion.

The claim is that bullish sentiment differs from its long-term average of 0.39.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.39\\\\H_a:\pi\neq 0.39$

The significance level is 0.05.

The sample has a size n=300.

The sample proportion is p=0.385.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.39*0.61}{300}}\\\\\\ \sigma_p=\sqrt{0.000793}=0.028$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.385-0.39+0.5/300}{0.028}=\dfrac{-0.003}{0.028}=-0.118$

This test is a two-tailed test, so the P-value for this test is calculated as:

$P-value=2\cdot P(z$

As the P-value (0.906) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that bullish sentiment differs from its long-term average of 0.39.

2) This is a hypothesis test for a proportion.

The claim is that bearish sentiment is above its long-term average of 0.30.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.3\\\\H_a:\pi\neq 0.3$

The significance level is 0.05.

The sample has a size n=300.

The sample proportion is p=0.399.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.3*0.7}{300}}\\\\\\ \sigma_p=\sqrt{0.0007}=0.026$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.399-0.3-0.5/300}{0.026}=\dfrac{0.097}{0.026}=3.679$

This test is a two-tailed test, so the P-value for this test is calculated as:

$P-value=2\cdot P(z>3.679)=0$

As the P-value (0) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that bearish sentiment is above its long-term average of 0.30.

3 0

3 years ago

I need the answer to this please.​

I need the answer to this please.