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3 years ago

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Identical net forces act for the same length of time on two different spherical masses. Which of the following describes the cha

nge in linear momentum of the smaller mass compared to that of the larger mass?
a. it is smaller than the change in linear momentum of the larger mass but not zero.
b. It is larger than the change in linear momentum of the larger mass.
c. It is equal to the change in linear momentum of the larger mass.
d. It is zero

1 answer:

Novosadov [1.4K]3 years ago

8 0

Answer:

the correct answer is c

Explanation:

In this exercise we seek the momentum

I = F t

this value is set because forces and time are given.

Now we can use the relationship between linear momentum and momentum

I = p_f - p₀

I = m v_f - m v₀

suppose that the two spheres depart with the same initial velocity

Let's analyze these results, the value of the impulse is the same, so the body of lower mass must acquire greater speed or momentum

consequently the lighter sphere acquires more final speed, but the change of momentum is the same in the two spheres

Consequently the correct answer is c

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explain why for thousands of years people believed that stars moved across Earth's sky. Explain why we now have a different expl

Anarel [89]

Answer:

Ptolemy proposed a model, he reference system is centered on the Earth

Copernicus, proposed a deferent system, this system is centered on the Sun, where it is at the origin of the system

Explanation:

Thousands of years ago, Ptolemy proposed a model to explain the movement of the planets and stars in the sky, in this model the reference system is centered on the Earth, so each body is orbiting in different spheres around the Earth as its center, this system had very complicated calculations and curves to be able to explain the orbits of the planets.

More recently Copernicus, proposed a deferent system, this system is centered on the Sun, where it is at the origin of the system, in this system the movement of the planets are ellipses, which is a much simpler explanation and has been widely accepted, in current systems the reference system is fixed in the bodies more massive, since this simplifies the explanation of the movements.

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3 years ago

The route followed by a hiker consists of three displacement vectors A with arrow, B with arrow, and C with arrow. Vector A with

kotykmax [81]

Answer:

$D_{B}=1173.98m\\D_{C}=675.29m$

Explanation:

If we express all of the cordinates in their rectangular form we get:

A = (1404.77 , 655.06) m

$B = A + ( -D_{B} *sin(41) , -D_{B} * cos(41) )$

$C = A + B + ( -D_{C} *cos(20) , D_{C} * sin(20) )$

Since we need C to be (0,0) we stablish that:

$C = (0,0) = A + B + ( -D_{C} *cos(20) , D_{C} * sin(20) )$

That way we make an equation system from both X and Y coordinates:

$A_{x} + B_{x} + C_{x} = 0$

$A_{y} + B_{y} + C_{y} = 0$

Replacing values:

$1404.77 - D_{B}*sin(41) - D_{C}*cos(20) = 0$

$655.06 - D_{B}*cos(41) + D_{C}*sin(20) = 0$

With this system we can solve for both Db and Dc and get the answers to the question:

$D_{B}=1173.98m$

$D_{C}=675.29m$

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4 years ago

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.1 m/s. The car is a distanc

Igoryamba

It's 61.5m

by solving simultaneously equations
29+d = 6t (bear)
d=4.1t (tourist)

6 0

3 years ago

Read 2 more answers

Which statement best describes how scientists and engineers work together

alexandr402 [8]

Answer:

Option D: Engineers come up with scientific questions when they are

developing their design, and scientists do research to answer

them.

Explanation:

Normally, scientists work involves study of how nature works while engineers work is to create new things, such as websites, products e.t.c. Now, the objectives of engineers and scientists are different because they follow different processes while working to achieve their results. Scientists perform experiments using the scientific method which involves processes such as constructing hypothesis and testing with an experiment while, engineers usually follow the creativity based design engineering processes which involves developing of prototype solutions and testing those solutions.

Thus, it's clear that engineers deal with design while scientists deal with research.

The correct answer will be option D

6 0

3 years ago

A light has a wavelength of 5.06x10-7m. what is the frequency of the light?

Artyom0805 [142]

So, the frequency of that light approximately $\sf{\bold{5.93 \times 10^{14} \: Hz}}$

<h3>Introduction</h3>

Hi ! Here I will help you to discuss the relationship between frequency and wavelength, with the velocity constant of electromagnetic waves in a vacuum. We all know that regardless of the type of electromagnetic wave, it will have the same velocity as the speed of light (light is part of electromagnetic wave too), which is 300,000 km/s or $\sf{3 \times 10^8}$ m/s. As a result of this constant property, <u>the shorter the wavelength, the greater the value of the electromagnetic wave frequency</u>. This relationship can also be expressed in this equation:

$\boxed{\sf{\bold{c = \lambda \times f}}}$

With the following condition :

c = the constant of the speed of light in a vacuum ≈ $\sf{3 \times 10^{8} \: m/s}$ m/s
$\sf{\lambda}$ = wavelength (m)
f = electromagnetic wave frequency (Hz)

<h3>Problem Solving</h3>

We know that :

c = the constant of the speed of light in a vacuum ≈ $\sf{3 \times 10^{8} \: m/s}$ m/s
$\sf{\lambda}$ = wavelength = $\sf{5.06 \times 10^{-7}}$ m.

What was asked :

f = electromagnetic wave frequency = ... Hz

Step by step :

$\sf{c = \lambda \times f}$

$\sf{3 \times 10^8 = 5.06 \times 10^{-7} \times f}$

$\sf{f = \frac{3 \times 10^8}{5.06 \times 10^{-7}}}$

$\sf{f \approx 0.593 \times 10^{8 - (-7)}}$

$\sf{f \approx 0.593 \times 10^{15}}$

$\boxed{\sf{f \approx 5.93 \times 10^{14} \: Hz}}$

<h3>Conclusion :</h3>

So, the frequency of that light approximately $\sf{\bold{5.93 \times 10^{14} \: Hz}}$

<h3>See More :</h3>

What affects photon energy brainly.com/question/26434060
What is the foton energy brainly.com/question/26518899

7 0

2 years ago