A 36-N crate is suspended from the left end of a plank. The plank weighs 21 N, but it is not uniform, so its center of gravity d
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Answer:
a) t = 3.2 s
b)
Explanation:
a) El tiempo requerido para llegar al suelo se puede calcular usando la siguiente fórmula:
En donde:
: es la altura inicial = 50 m
g: es la gravedad = 10 m/s²
Entonces, el tiempo requerido para llegar al suelo es 3.2 s.
b) La rapidez de la pelota justo antes del choque es el siguiente:
En donde:
: es la velocidad inicial = 0 (dado que se deja caer en resposo)
Por lo tanto, la rapidez de la pelota justo en el momento anterior del choque es -32 m/s (el signo negativo es porque la pelota está cayendo).
Espero que te sea de utilidad!
Answer:
No, it is not conserved
Explanation:
Let's calculate the total kinetic energy before the collision and compare it with the total kinetic energy after the collision.
The total kinetic energy before the collision is:
where m1 = m2 = 1 kg are the masses of the two carts, v1=2 m/s is the speed of the first cart, and where v2=0 is the speed of the second cart, which is zero because it is stationary.
After the collision, the two carts stick together with same speed v=1 m/s; their total kinetic energy is
So, we see that the kinetic energy was not conserved, because the initial kinetic energy was 2 J while the final kinetic energy is 1 J. This means that this is an inelastic collision, in which only the total momentum is conserved. This loss of kinetic energy does not violate the law of conservation of energy: in fact, the energy lost has simply been converted into another form of energy, such as heat, during the collision.