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2 years ago

15

Why do we need to square the period for pendulum experiment? How it is related to obtaining gram ?

1 answer:

andreev551 [17]2 years ago

6 0

Answer:

The period of a pendulum does not depend on the mass of the ball, but only on the length of the string. Two pendula with different masses but the same length will have the same period. Two pendula with different lengths will different periods; the pendulum with the longer string will have the longer period.

Explanation:

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How would changing the proportions of substances in an alloy change its properties

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3 years ago

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Two deuterium nuclei, H, fuse to produce a tritium nucleus, H, and a hydrogen nucleus. A neutral deuterium atom has a mass of 2.

Nesterboy [21]

<u>Answer:</u> The amount of energy released in the process is 4.042 MeV.

<u>Explanation:</u>

The chemical reaction for the fusion of deuterium nucleus follows the equation:

$_1^2\textrm{H}+_1^2\textrm{H}\rightarrow _1^3\textrm{H}+_1^1\textrm{H}$

Atomic mass of the nucleus also contains some mass of the electrons.

Mass of electron in $MeV/c^2$ is $0.511MeV/c^2$

<u>Calculating the mass of deuterium nucleus:</u>

$m(_1^2\textrm{H})=(2.014102u)\times (931.494MeV/c^2.u)-\text{Mass of electron}$

So, initial mass of the reaction = $2[(1876.124MeV/c^2)-(0.511MeV/c^2)]=3751.226MeV/c^2$

<u>Calculating the mass of tritium nucleus:</u>

$m(_1^3\textrm{H})=(3.106049u)\times (931.494MeV/c^2.u)-\text{Mass of electron}$

$m(_1^3\textrm{H})=(3.106049u)\times (931.494MeV/c^2.u)-(0.511MeV/c^2)=2803.921MeV/c^2$

So, final mass of the reaction = $2803.921-[(1.007267u\times 931.494MeV/c^2.u)]=3747.184$

Difference between the masses of the nucleus:

$\Delta m=m_{initial}-m_{final}\\\\\Delta m=(3751.226-3747.184)MeV/c^2=4.042MeV/c^2$

Energy released in the process is calculated by using Einstein's equation, which is:

$E=\Delta mc^2$

Putting value of $\Delta m$ in above equation, we get:

$E=(4.042MeV/c^2)\times c^2\\\\E=4.042MeV$

Hence, the amount of energy released in the process is 4.042 MeV.

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3 years ago