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Gwar [14]
3 years ago
5

1. Name the ray in the figure

Mathematics
1 answer:
oee [108]3 years ago
4 0

Answer:

The correct answer is option c.

Step-by-step explanation:

Have a nice Day!

and can I maybe have brainliest? Thanks!

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SOME PLEASE HELP OMG
Ilia_Sergeevich [38]

Answer: 3x plus 36

Step-by-step explanation:

You multiply inside the brackets by 3 and you get 3x+36

7 0
3 years ago
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Y= - 2x + 4<br> 2x + y = 4
Tomtit [17]

Answer:

Infinite amount of solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -2x + 4

2x + y = 4

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                                                                                                  2x + (-2x + 4) = 4
  2. Combine like terms:                                                                                         4 = 4

Here we see that 4 does indeed equal 4.

∴ the systems of equations has an infinite amount of solutions.

7 0
3 years ago
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Brad has 42 stamps to arrange on an album page
grin007 [14]

Answer:

6×7 =42

I think it suitable

5 0
3 years ago
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The midpoint between y and 31= -5<br> What is y<br><br> Giving 10pts
Fynjy0 [20]

Answer:

this question doesnt have a solution it makes no sense

Step-by-step explanation:

6 0
3 years ago
Ryan invested $5,900 in an account paying an interest rate of 5% compounded
vladimir1956 [14]

Answer:

10214.51

Step-by-step explanation:

5900 * (1+ (0.05/12))^(12*11)

please give brainliest

4 0
3 years ago
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