Answer:
-4
Step-by-step explanation:
Answer:
He has 11 quarters
Step-by-step explanation:
* Lets study the information in the problem to solve it
- The value of dimes and quarters is $6.35
- There are dimes and quarters
- The dime = 10 cents
- The quarter = 25 cents
* We must change the money from dollars to cents
∵ $1 = 100 cents
∴ $6.35 = 6.35 × 100 = 635 cents
- The number of dimes = 3 + 3 × number of quarters
* Let number of dimes is D and number of quarter is Q
∴ D = 3 + 3Q
∴ 10D + 25Q = 635
* Substitute the value of D from first equation in the second equation
∴ 10(3 + 3Q) + 25Q = 635 ⇒ open the bracket
∴ 10(3) + 10(3Q) + 25Q = 635
∴ 30 + 30Q + 25Q = 635 ⇒ collect like terms
∴ 30 + 55Q = 635 ⇒ subtract 30 from both sides
∴ 55Q = 605 ⇒ divide both sides by 55
∴ Q = 11
* He has 11 quarters
For this problem all you have to do is plug in the value that they is in parenthesis for x. If it says g (x) = x and then it asks g(5) = ?, it is saying what happens if i put 5 in for every x. in this case it would be g (5) = 5. I just replaced x with 5.
So g (-2) we sub -2 for x
g (-2) = -2 (-2)^2 + 3 (-2) - 5
= -2 (4) - 6 - 5
= -19
g (0) = -2 (0) + 3 (0) - 5
= 0 + 0 - t
= -5
g (3) = -2 (3)^2 + 3 (3) - 5
= -18 + 9 - 5
= -14
I am not sure but I think you have to multiply 538 and 9 and get 4842 then divide 4842 by 15 and get 322.8. ( I am not sure if I'm right ).
4. When reading the stem and leaf plot the only values that fall between the range of 40 < x <60 is the 4 values of 45. They are located at the tail end of the 4 stem after the zeros. The 40s and 60s are not counted because it is not mentioned equal to 40 or 60.
