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Naddik [55]
3 years ago
5

Determine the number of terms in each algebraic expression (6a+9)-7b​

Mathematics
2 answers:
jekas [21]3 years ago
7 0

Answer:

There are three terms, which means it is trinomial expression.

the first term is 6a

the second term is 9 and

the third term is -7b

Vesnalui [34]3 years ago
3 0

Answer:

3

Step-by-step explanation:

(6a+9)-7b

There are 3 terms

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It is easy all you have to do is 15-3 because 1+2=3
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________________________
xenn [34]

✩ Answer:

 ✧・゚: *✧・゚:*✧・゚: *✧・゚:*✧・゚: *✧・゚:*  

 \bold{Hello!}\\\bold{Your~answer~is~below!}  

✩ Step-by-step explanation:

 ✧・゚: *✧・゚:*✧・゚: *✧・゚:*✧・゚: *✧・゚:*

✺ Divide both sides by −3. Since −3 is negative, the inequality direction is changed:

  • -3 ÷ -3 = Cancels Out
  • Turns into: \frac{-9}{-3} >5x-2

✺ Divide −9 by −3 to get 3. Since they are both negatives it turns into a positive:

  • -9 ÷ -3 = 3
  • Turns into: 3 > 5x - 2

✺ Swap sides so that all variable terms are on the left hand side. This changes the sign direction once more:

  • Turns into: 5x-2

✺ Add 2 to both sides:

  • Turns into: 5x

✺ Add 3 and 2 to get 5:

  • 3 + 2 = 5
  • Turns into: 5x

✺ Divide both sides by 5. Since 5 is positive, the inequality direction remains the same:

  • 5 ÷ 5 = Cancels Out
  • Turns into: x

✺ Divide 5 by 5 to get 1:

  • 5 ÷ 5 = 1

✺  So your answer is B, \boxed{x.

(Number line is below.)

Hope~this~helps~and,\\Best~of~luck!\\\\~~~~~-TotallyNotTrillex

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3 years ago
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Prove that<br><img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B3%7D%20%20%5Ctimes%20%20%7B3%7D%5E%7B0%7D%20%20%2B%20%20%7B3%7D%
KonstantinChe [14]

Answer:

Step-by-step explanation:

Anything raise to the power zero is 1

Therefore,

               LHS\\\\ =2^3 \times 3^0 + 3^2 \times 2^0\\\\8 \times 1 + 9 \times 1 \\\\17

LHS = RHS

Hence Proved

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Jenny drove 638 miles and 11 hours at the same rate how many miles would she drive-in 7 hours
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Jenny would drive 406 miles
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Lim (sin x )^tanx as x-&gt;pi/2
Sholpan [36]
 <span>lim (x → π/2) (sinx)^(tanx) 
= lim (x → π/2) e^[(tanx) ln (sinx)] 
= e^ [lim (x → π/2) (tanx) ln (sinx)] ... (1) 

lim (x → π/2) (tanx) ln (sinx) 
= lim (x → π/2) [ln(sinx) / cotx] 

Using L'Hospital'stheorem, 
= lim (x → π/2) [- cotx / cosec^2 x] 
= 0 

Plugging in ( 1 ), 
required limit = e^0 = 1 

=>Answer is 1.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
3 0
4 years ago
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