First, we will need to compute the quotient of 4 and 1/5
When we divide a number by a fraction, we convert the division to multiplication and then flip this fraction.
Therefore, in the given:
4 / (1/5) we will convert the division into multiplication and flip the 1/5 to 5
This will result is the following:
4 / (1/5) = 4*5 = 20
Comparing this quotient to 4, we will find that the quotient is greater than 4
Therefore, the given statement is: True
Let's x represents the first odd integer
The next consecutive integer would be represented as x+2.
So x and x+2 being multiplied together will give us 1443:
(x)(x+2)=1443
x^2+2x=1443
x^2+2x-1443=0
By solving the quadratic equation using the quadratic formula, x will equal to 37 and -39.
Since the problem says "integers", so I'm assuming two pairs of consecutive integers would be ok.
With that said you 1st pair will be: 37,39
Your second pair will be: -37,-39.
Answer:
#1) D frequency data that can be plotted on a number line
; #2) A Sarah read twice as many chapters Wednesday as Monday, C Sarah read more than four chapters on two days, F Sarah read at least three chapters on four days, and H The total number of chapters Sarah read on the weekend was the same as the total number she read on the weekdays.
Step-by-step explanation:
#1) A line plot shows the frequencies of data. It is displayed over a number line; this makes the best choice for the answer "frequency data that can be plotted on a number line."
#2) We can see that Sarah read 2 chapters on Wednesday and 1 chapter on Monday. This is twice as many chapters.
She read more than 4 chapters on both Saturday and Sunday.
She read 3 or more chapters on Tuesday, Friday, Saturday and Sunday.
The total number of chapters she read on the weekend was 5+6 = 11. The total number of chapters she read on the weekdays was 1+3+2+2+3 = 11. These are the same.
Answer:
an = 67 -11(n -1)
Step-by-step explanation:
The terms of your arithmetic sequence have a common difference of -11. The first term is 67.
These values can be used in the generic formula for the n-th term:
an = a1 +d(n -1) . . . . . . first term a1, common difference d
an = 67 -11(n -1) . . . . . formula for the n-th term
