3 years ago

Find the probability.

Mathematics

1 answer:

sasho [114]3 years ago

8 0

Answer:

excellent this is ur correcoting answer

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(y-5)(y+7)

Step-by-step explanation:

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3 years ago

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2 years ago

Daily low temperatures in Columbus, OH in January 2014 were approximately normally distributed with a mean of 15.45 and a standa

Alona [7]

Answer: 12.10

Step-by-step explanation:

Given : Mean : $\mu = 15.45$

Standard deviation : $\sigma = 13.70$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x= 5 degrees

$z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76$

For x= 10 degrees

$z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40$

The P-value : $P(-0.76$

$=0.3445783-0.2236273=0.120951\approx0.1210$

In percent , $0.1210\times100=12.10\%$

Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%

5 0

2 years ago

If 9a + 9b + 9c = 59a+9b+9c=5 ,<br><br>what is 72a + 72b + 72c72a+72b+72c?

Gekata [30.6K]

Answer:

Step-by-step explanation:

9a + 9b + 9c = 5

Multiply the equation by 8

8*(9a + 9b + 9c )= 5*8

Distribute

72a +72b +72 c = 40

6 0

3 years ago