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3 years ago

Please help me this is for a grade

Mathematics

1 answer:

IgorC [24]3 years ago

4 0

Answer:

Step-by-step explanation:

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WILL MAKE YOU BRAINLIEST! PLEASE ANSWER THIS FAST! BRAINLIEST, 5 STARS, AND A THANKS! EASY QUESTION! 6TH GRADE MATH!

katovenus [111]

Answer:

Step-by-step explanation:

I got it wrong because of the previous user but here is the correct answer with proof from K12!

3 0

4 years ago

The following equation involves a trigonometric equation in quadratic form. Solve the equation on the interval [0,2π).

Effectus [21]

Answer:

$\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}$

Step-by-step explanation:

Given the quadratic equation as:

$2sin^2x+sinx=1\\OR\\2sin^2x+sinx-1=0$

Let us put $sinx=y$ for simplicity of the equation:

Now, the equation becomes:

$2y^2+y-1=0$

Now, let us try to solve the quadratic equation:

$\Rightarrow 2y^2+2y-y-1=0\\\Rightarrow 2y(y+1)-1(y+1)=0\\\Rightarrow (2y-1)(y+1)=0\\\Rightarrow 2y-1 = 0, y+1 = 0\\\Rightarrow y = \dfrac{1}{2}, y = -1$

So, the solution to the given trigonometric quadratic equation is:

$sinx = \dfrac{1}{2}$

and

$sinx=-1$

Let us try to find the values of $x$ in the interval $[0, 2\pi)$ .

$sin\theta$ can have a value equal to $\frac{1}{2}$ in 1st and 2nd quadrant.

So, $x$ can be

$30^\circ, 150^\circ\\OR\\\dfrac{\pi}{6}, \dfrac{5\pi}{6}$

For $sinx=-1$ ,

$x = 270^\circ\ or\ \dfrac{3 \pi}{2}$

So, the answer is:

$\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}$

7 0

3 years ago

50 points! please help!.

Sunny_sXe [5.5K]

Answer:

Solution given:

Sin $\theta_{1}=\frac{-24}{25}$

$\frac{opposite}{hypotenuse}=\frac{-24}{25}$

equating corresponding value

opposite=-24

hypoyenuse=25

adjacent=x

By using Pythagoras law

hypotenuse²=opposite²+adjacent²

25²=(-24)²+x²

625=576+x²

x²=625-576

x=49

x= $\sqrt{49}=7$

In IV quadrant

Cos angle is positive

Cos $\theta_{1}=\frac{adjacent}{hypotenuse}$

<h3>Cos $\theta_{1}=\frac{7}{25}$ </h3>

8 0

3 years ago

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Whats 2+2................................

Rama09 [41]

Answer:

4.0

Step-by-step explanation:

3 0

3 years ago

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A triangle has side lengths measuring 20 cm, 5 cm, and n cm. Which describes the possible values of n? 5 < n < 15 5 < n

ehidna [41]

Answer:

15 < n < 25

Step-by-step explanation:

According to the triangle inequality theorem, any two sides lengths' sum should be greater than the third side. This also implies that to find the <em>possible length of the 3rd side given other two sides (let two given sides be x and y)</em>, we can say that the 3rd side length will be between x+y and x-y.

Hence, we can say that <em><u>n should be between 20+5 and 20-5</u></em>.

So, 20 - 5 < n < 20 + 5, which is

15 < n < 25

<em>This is the correct answer.</em>

5 0

3 years ago

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