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iris [78.8K]
3 years ago
8

Which of the following graphs has the largest average rate of change from -1 to 2?​

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
3 0

Answer:

i dont know either

Step-by-step explanation:

konstantin123 [22]3 years ago
3 0

Answer:

-2 it should be enojy you answer

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Need help with two of these! Thank you
astraxan [27]

Step-by-step explanation:

17) 3x+5-12+4x+2x

3x+4x+2x +5-12

8x-7

if x =6

8*6-7 =48-7

= 41

18.) 9(3x-4y+8)

27x-36y+72

6 0
2 years ago
A card is drawn randomly from a standard 52-card deck. Find the probability of the given event.
irakobra [83]

Answer:

a). 1/13

There are 4 5s. so 4/52

b). 3/13

12 total jack, king, and queen. 12/52

c). 15/26

30 cards are not face cards so 30/52

8 0
2 years ago
What are the real roots of 2x^3+9x^2+4x-15=0
klemol [59]
Well, luckily it is apparent that (x-1) is a root because when x=1 the equation is equal to zero.  So we can divide the equation by that factor to find the other roots. 

(2x^3+9x^2+4x-15)/(x-1)
2x^2  r  11x^2+4x-15
11x    r  15x-15
15     r   0

(x-1)(2x^2+11x+15)=0

(x-1)(2x^2+6x+5x+15)=0

(x-1)(2x(x+3)+5(x+3))=0

(x-1)(2x+5)(x+3)=0

So the roots are x= -3, -2.5, 1
8 0
3 years ago
The total cost of Anja’s trip to the dentist was $628.35. She paid a flat fee of $89.95 which included the checkup and cleaning
Anna11 [10]
4x + 89.95 = 628.35 <== ur equation
4x = 628.35 - 89.95
4x = 538.40
x = 538.40 / 4
x = 134.60 <== the cost for each cavity filling
8 0
3 years ago
Read 2 more answers
How many women must be randomly selected to estimate the mean weight of women in one age group.we want 90% confidence that the s
mojhsa [17]
That is a very good question....

Look Grank

you know that:

confidence interval = mean +or- Margin of Error

and

Margin of Error = (z)*(standard deviation) / (sqrt of n)
where n is the number of sample records

So we need to calculate z-value firstly

It says: "<span>we want 90% confidence"

So that:
</span>
<span>confidence90% corresponds to z-value of 1.645

Plug that into our formula of </span><span>Margin of Error:

</span>Margin of Error = (1.645)*(22) / (sqrt of n)

"The sample mean is within 2.7 lb of the population mean" means that Margin of Error is 2.7

<span>Margin of Error:

</span>2.7 = (1.645)*(22) / (sqrt of n)

Now solve for n:

n=179.66~180

SO that 180<span> women must be randomly selected to estimate the mean weight of women in one age group.</span>
7 0
3 years ago
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