All categories

3 years ago

Find the unknown value in the proportion: 7⁄15 = x⁄75

Mathematics

2 answers:

Zina [86]3 years ago

6 0

$\frac{7}{15} = \frac{x}{75}$ Multiply 75 to both sides of the equation

$(75)\frac{7}{15} =\frac{x}{75} (75)$

$\frac{525}{15} =x$

35 = x

riadik2000 [5.3K]3 years ago

3 0

We just need to multiply in a x format.

7/15 = x/75

Multiply 7 with 75 and 15 with x.

7 . 75 = 15 . x

525/15 = x

x = 35

You might be interested in

I asked my dad how to solve this question and he part helped me and I was like ohhhhhhhhhhh so now I want you to solve it. I'll

matrenka [14]

Answer:

Whats the question? I can surely answer it.

3 0

3 years ago

Are the ratios 25/45 and 15/27 proportional? Explain.

liberstina [14]

Write them out as a fraction then reduce them. If theyre the same then its proportional.

25/45 can be cancelled down to 5/9

15/27 can be cancelled down to 3/9

So no theyre not.

6 0

3 years ago

HELP ASAP, DUE AT 11:59<br><br> g(-5)=

Dovator [93]

Answer:

g(-5) = -6

Step-by-step explanation:

We need to find value of g(-5)

Looking at the graph in figure when g = -5, the value on the graph is -6 as it is highlighted with blue point.

because we have x = -5 so, we will look at graph that passes through x and y when x= -5, so we get y=-6

So, g(-5) = -6

6 0

3 years ago

A diver descends to a depth of –25.6 feet relative to sea level. How many feet must the diver ascend to reach sea level?

MArishka [77]

Answer:

the Answer would be c

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles.

diamong [38]

Answer:

$\dfrac{6}{55}$

$\dfrac{4}{165}$

Step-by-step explanation:

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles. There are 11 marbles in total.

A. The probability that the first marble drawn is blue marble is

$\dfrac{4}{11},$

the probability that the second marble drawn is red marble is

$\dfrac{3}{10}$

The probability that the first marble drawn is blue and the second is red is

$\dfrac{4}{11}\cdot \dfrac{3}{10}=\dfrac{12}{110}=\dfrac{6}{55}$

B. The probability that the first marble drawn is red marble is

$\dfrac{3}{11},$

the probability that the second marble drawn is white marble is

$\dfrac{4}{10}$

The probability that the first marble drawn is red and the second is white is

$\dfrac{3}{11}\cdot \dfrac{4}{10}=\dfrac{12}{110}=\dfrac{6}{55}$

C. The probability that the first marble drawn is blue marble is

$\dfrac{4}{11},$

the probability that the second marble drawn is blue marble is

$\dfrac{3}{10},$

the probability that the third marble drawn is blue marble is

$\dfrac{2}{9},$

The probability that the first, second and third marbles drawn are blue is

$\dfrac{4}{11}\cdot \dfrac{3}{10}\cdot \dfrac{2}{9}=\dfrac{24}{990}=\dfrac{4}{165}$

8 0

3 years ago