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andrew11 [14]
3 years ago
14

30. The entire molecule shown in the diagram below is the building block for RNA and is called a(n)

Biology
1 answer:
arlik [135]3 years ago
7 0

Answer:

Nitrogen Base/Nucleotide

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PLS HELP I WILL GIVE BRAINLIST
ra1l [238]

There are four bases found in DNA: adenine (A), cytosine (C), guanine (G), and thymine (T). Adenine forms a base pair with thymine, and cytosine forms a base pair with guanine. There is a one-to-one relationship in these base pairings (Chargaff’s rule), which means that if you know the percentage of any one of them within a given DNA sample, you can calculate the percentages of the other three. In this case, you're given the percentage of guanine, and you want to find out the percentage of adenine.

Since guanine base-pairs with cytosine and since there must be as much cytosine as there is guanine, 41% of the bases in this gene are cytosine as well. That means that adenine and thymine <em>together </em>make up the remaining 18% (100% − 41% G − 41% C) of the base pairs. If there must be an equivalence in the number of thymine and adenine bases per Chargaff's rule, then half of the remaining base pairs must comprise adenine and the other half comprise thymine. Half of 18% is 9%.

Thus, adenine makes up 9% of the bases in this gene.

5 0
3 years ago
A scientific theory
Karo-lina-s [1.5K]

Answer:

the answer should be c

Explanation:

4 0
3 years ago
Read 2 more answers
The process by which rods and cones convert
jeyben [28]
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6 0
4 years ago
PLEASE HELP ME
Ainat [17]

Answer:

c

Explanation:

planets are round because of their gravitational field acts as though it pulls everything from the center of its body and pulls everything toward it

3 0
3 years ago
You are following segregation of five unlinked genes in a cross – A, B, C, D and E. Dominant alleles are capital letters and rec
bija089 [108]

Answer:

1/64 = 0.015625

Explanation:

Genotype of parents:  aa bb Cc Dd Ee x aa Bb Cc dd Ee

To calculate the frequency of the child with desired genotype, individual frequency of desired genotype can be calculated followed by application of product rule.

aa x aa = All aa

bb x Bb= 1/2 bb: 1/2 Bb

Cc x Cc= 1/4 CC: 1/2 Cc : 1/4 cc

Dd x dd = 1/2 Dd: 1/2 dd

Ee x Ee= 1/4 EE: 1/2 Ee: 1/4 ee

Expected frequency of the child with desired genotype= 1 aa x 1/2 bb x 1/4 cc x 1/2 dd x 1/4 ee = 1/2 x 1/4 x 1/2 x 1/4 = 1/64 = 0.015625

6 0
3 years ago
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