(x - a)^2 + (y - b)^2 = (y - d)^2
<span>x^2 - 2ax + a^2 + y^2 - 2by + b^2 = y^2 - 2dy + d^2 </span>
<span>Subtract y^2 from both sides... </span>
<span>x^2 - 2ax + a^2 - 2by + b^2 = -2dy + d^2 </span>
<span>Now I would just substitute in the the values (a = -4, b = 17/8, d = 15/8)... </span>
<span>x^2 - 2(-4)x + (-4)^2 - 2(17/8)y + (17/8)^2 = -2(15/8)y + (15/8)^2 </span>
<span>Simplify... </span>
<span>x^2 + 8x + 16 - (17/4)y + 289/64 = -(15/4)y + 225/64 </span>
<span>Add (17/4)y to both sides... </span>
<span>x^2 + 8x + 16 + 289/64 = (2/4)y + 225/64 </span>
<span>x^2 + 8x + 16 + 289/64 = (1/2)y + 225/64 </span>
<span>Subtract 225/64 from both sides... </span>
<span>x^2 + 8x + 16 + 1 = (1/2)y </span>
<span>x^2 + 8x + 17 = (1/2)y </span>
<span>Multiply both sides by 2... </span>
<span>2x^2 + 16x + 34 = y </span>
<span>...which is equal to equation D.</span>
Hello there!
The correct answer is option C
I hope this helps!
As always, I am here to help people like you!
1. Multiply x and 3y by x-2
x^2-2x (i.e. x*x=x^2, -2*x=-2x)
3yx-6y (i.e. 3y*x=3yx, 3y*2=6y)
2. Multiply x+y by -4
x*-4= -4x
y*-4=-4y
3. Multiply 2x+3y by -1
2x*-1=-2x
3y*-1=-3y
4. Combine like terms
x^2 3yx -2x -6y
-2x -3y
-4x -4y
-------------------------------------------
x^2 +3yx -8x -13y
Hope this helps!
Answer:
I got 15 and 12
PLZ CORRECT ME IF I AM WRONG PLEASE AND THanK YOU
Step-by-step explanation:
The answer is A. You need an additional angle and the side must be between the two angles. It's called the 'included' side.
ASA means Angle, Side, Angle