Lets put the numbers in order...
6,7,7,8,8,9,9,10,11,30
Q1 = 7
Q2 = (8 + 9) / 2 = 17/2 = 8.5
Q3 = 10
IQR = Q3 - Q1 = 10 - 7 = 3 <== so the interquartile range is 3
mean absolute deviation...
the mean of our data is 10.5
now we subtract the mean from every data point....and find its absolute value
6 - 10.5 = -4.5.....| -4.5| = 4.5
7 - 10.5 = -3.5.....| -3.5| = 3.5
7 - 10.5 = -3.5.....|-3.5| = 3.5
8 - 10.5 = - 2.5....|-2.5| = 2.5
8 - 10.5 = -2.5....|-2.5| = 2.5
9 - 10.5 = -1.5....|-1.5| = 1.5
9 - 10.5 = -1.5....|-1.5| = 1.5
10 - 10.5 = -0.5..| -0.5| = 0.5
11 - 10.5 = 0.5...|0.5| = 0.5
30 - 10.5 = 19.5..|19.5| = 19.5
now we take the average of these numbers
(4.5+3.5+3.5+2.5+2.5+1.5 + 1.5 + 0.5+0.5+19.5) / 10 =
40/10 = 4 <== ur mean absolute deviation
In summary :
ur interquartie range (IQR) of ur data set is 3
ur mean absolute deviation (MAD) of ur data set is 4
Answer:
Step-by-step explanation:
(-1,6)(2,-6)
slope = (-6 - 6) / (2 - (-1) = -12/3 = -4
y = mx + b
slope(m) = -4
(-1,6)...x = -1 and y = 6
sub and find b, the y int
6 = -4(-1) + b
6 = 4 + b
6 - 4 = b
2 = b
so the equation is : y = -4x + 2 <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(-1,6)...x1 = -1 and y1 = 6
sub
y - 6 = -4(x - (-1) =
y - 6 = -4(x + 1) <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(2,- 6)...x1 = 2 and y1 = - 6
sub
y - (-6) = -4(x - 2) =
y + 6 = -4(x - 2) .... here is one, but it is not an answer choice
1 mile = 1.6km.
so
100 miles x 1.6km = 160.
The number of km between two cities is 160km.
Answer:
x=13.5
Step-by-step explanation:
Using the formula:
Sin theta=opposite/hypotenuse
Where theta=57 degrees
opposite =10.8
hypotenuse =x
Sin57=10.8/x
Xsin57=10.8
x=10.8/sin57
x=10.8/0.8
x=13.5
