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2 years ago

What is next number in pattern 7, 11, 2, 18, -7

Mathematics

1 answer:

Helga [31]2 years ago

6 0

Answer:

the answer is -7+-25=-32

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Which equation would you use to solve this problem?

const2013 [10]

I have no idea what is is but try 4 or 1,If not you should go on cymath

8 0

3 years ago

Read 2 more answers

(w-x)^2 + 26x; if w = 6 and x = -1

kati45 [8]

Answer:

$\boxed{\boxed{\sf 23}}$

Step-by-step explanation:

$\boxed{\sf Hi\: there!}$

$\sf (w-x)^2 + 26x$

$\sf w=6$

$\sf x=-1$

_____________________

→ $\sf \left(6-\left(-1\right)\right)^2+26\left(-1\right)$

→ $\sf 23$

»»————-　➴　————-««

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2 years ago

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What is the value of x? x+10 105

sashaice [31]

X+10=105
105-10=95=x
x = 95

6 0

2 years ago

I will give BRAINLIEST to the correct answer Find the measure of angle 6.

True [87]

Answer:

m∠6 = 116°

Step-by-step explanation:

first find x:

7x - 17 = 2x + 78

subtract 2x from both sides: 5x - 17 = 78

add 17 to both sides: 5x = 95

divide by 5: x = 19

plug x into 7x - 17

7(19) - 17 = 116

∠6 and 7x - 17 are vertical angles and therefore congruent, so m∠6 also = 116°

3 0

2 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0

1 year ago