Answer:
a. Plan B; $4
b. 160 mins; Plan B
Step-by-step explanation:
a. Cost of Plan A for 80 minutes:
Find 80 on the x axis, and trave it up to to intercept the blue line (for Plan A). Check the y axis to see the value of y at this point. Thus:
f(80) = 8
This means Plan A will cost $8 for Rafael to 80 mins of long distance call per month.
Also, find the cost per month for 80 mins for Plan B. Use the same procedure as used in finding cost for plan A.
Plan B will cost $12.
Therefore, Plan B cost more.
Plan B cost $4 more than Plan A ($12 - $8 = $4)
b. Number of minutes that the two will cost the same is the number of minutes at the point where the two lines intercept = 160 minutes.
At 160 minutes, they both cost $16
The plan that will cost less if the time spent exceeds 160 minutes is Plan B.
Answer:
a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they are in favor of making the Tuesday before Thanksgiving a holiday, or they are against. This means that we can solve this problem using concepts of the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
So, the binomial probability distribution has two parameters, n and p.
In this problem, we have that 
and 
. So the parameter is
a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.
0.3(4x-8)-0.5(2.4x+4)
1.2x-2.4-1.2x+2
x-0.4
Answer:
4
Step-by-step explanation:
In statistics and probability theory, the median is the value separating the higher half from the lower half of a data sample, a population or a probability distribution. For a data set, it may be thought of as the "middle" value. And the middle value in this problem is 4.
