G(x) = -f(x + 3)? what is the vertex?

Someone help solve ill gift you nitro :)

Tems11 [23]

1/3•3.14•. r^2 •h

1/3•3.14•20^2•25

10466.6667

that rounds up to 10,467.

I could be wrong though!

hope this helps! :)

7 0

3 years ago

Round 7 3/8 to the nearest whole number?!?

DIA [1.3K]

Answer:

7

Step-by-step explanation:

Everything including 1/2 and above rounds up to the next whole number.

3/8 < 4/8

7 and 3/8 rounds to 7

5 0

3 years ago

Leno4ka [110]

Answer:

6°F

58°F

Step-by-step explanation:

From the data Given :

Temperature rise in Buffalo by noon time = 14°F

The initial temperature at Buffalo = - 8°F

Rise in temperature = 14°F

Therefore, temperature at noon = (-8 + 14)°F = 6°F

B.)

Temperature at 6am in St. Louis = 32°F

Temperature at 6am in Juneau = - 26°F

Temperature difference :

(32 - (-26))°F

32 + 26

= 58°F

Temperature in St. Louis is 58°F higher

8 0

3 years ago

Ethan’s favorite kind of exercise is running. He runs on a path that is 1.75 miles long. Last week, Ethan ran on the path 6 time

Basile [38]

Answer:

10.5 miles

Step-by-step explanation:

You multiply the distance with the number of times he ran.

7 0

3 years ago

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0

3 years ago