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IgorC [24]
3 years ago
10

1.50x - 7.55 = -15.05 what is the answer

Advanced Placement (AP)
2 answers:
emmasim [6.3K]3 years ago
5 0
=−5 is the solution
eduard3 years ago
5 0
The answer is -7.5/1.50
The simplified answer is x = -5
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Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

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C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2

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0\times e^{4-0^2} = 0 and 2\times e^{4-2^2} = 2

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\frac{\mathrm{d} \left (t\times e^{4-t^2}   \right )}{\mathrm{d} x}=0

From which we have;

\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0

e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0

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For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

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For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

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Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

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