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3 years ago

Find me shape of the line through the pair of points: 1) (6,7) and (-3,5)

Mathematics

1 answer:

zvonat [6]3 years ago

8 0

Answer:

Slope of the line through the pair of points: (6,7) and (-3,5) is $\mathbf{-\frac{2}{3}}$

Step-by-step explanation:

Find me shape of the line through the pair of

points:

1) (6,7) and (-3,5)

<em>(Note: Correction. I assume there is spelling mistake and you need to find slope of line and not shape)</em>

The slope of line can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We are given points (6,7) and (-3,5)

We can write: x_1=6, y_1=7, x_2=-2, y_2=5

Now, putting values in the formula and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{5-7}{-3-(-6)}\\Slope=\frac{5-7}{-3+6}\\Slope=\frac{-2}{3}$

So, the slope is $-\frac{2}{3}$

Therefore, Slope of the line through the pair of points: (6,7) and (-3,5) is $\mathbf{-\frac{2}{3}}$

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In a reliability test there is a 42% probability that a computer chip survives more than 500 temperature cycles. If a computer c

Strike441 [17]

Answer:

The probability is $P(B' n A ' ) =$ 16%

Step-by-step explanation:

From the question we are told that

A is the event that the chip was "made by company A"

B is the event that a chip "survives 500 temperature cycles"

The probability that a computer chip survives more than 500 temperature cycles is

$P(B) = 42$ % $= 0.42$

The probability that does not survive more than 500 temperature cycles and it was manufactured by company A is $P(A | B' ) = 0.73$

The probability that the computer chip is not manufactured by company A and does not survive more than 500 temperature cycles is mathematically evaluated as

$P(B' n A ' ) = P (B' | A' ) P(B ')$

Where $B' \ and \ A'$ are a A and B complements and | represented AND operator

$P(B' n A ' ) = [1 - P (B' | A )] [1 - P(B )]$

substituting values

$P(B' n A ' ) = [1 - 0.73] [1 - 0.42 ]$

$P(B' n A ' ) = (0.27 )(0.58)$

$P(B' n A ' ) =0.16$

$P(B' n A ' ) =$ 16%

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3 years ago

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Step-by-step explanation:

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Step-by-step explanation:

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Identify the three similar right triangles in the given diagram.

irga5000 [103]

Answer:

B. ΔABD, ΔADC, ΔDBC

Step-by-step explanation

Step -1 In ΔABD and ΔADC (from figure).

∠DAB=∠CAD (common in both triangles) ,

∠DBA=∠CDA =90 degree, and

∠BDA=∠DCA (rest angle of the two triangles).

therefore ΔABD similar to ΔADC (by AAA similarity theorem).

Step -2 In ΔDBC and ΔADC (from figure).

∠DCB=∠ACD (common in both triangles) ,

∠DBC=∠ADC =90 degree, and

∠CDB=∠CAD (rest angle of the two triangles).

therefore ΔDBC similar to ΔADC (by AAA similarity theorem).

Step -3 In ΔABD and ΔDBC (from figure).

∠BDA=∠BCD (because , ∠ACD=ADB from stap-1 and ∠ACD=∠BCD from figure) ,

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∠BAC=∠BDC (rest angle of the two triangles).

therefore ΔABD similar to ΔDBC (by AAA similarity theorem).

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Hence ΔABD, ΔADC, ΔDBC similar to each other in the given figure.

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