The mass of 5 m' of copper is 44 800 kg. Work out<br> the density of copper.

2+ 4/5 + 1 1/2 please help<br><br>

vlabodo [156]

Answer:

Step-by-step explanation:

11/2=55/10

2=20/10

4/5=8/10

55+20+8/10=83/10

6 0

3 years ago

In ΔUVW, the measure of ∠W=90°, UV = 6.2 feet, and WU = 1.2 feet. Find the measure of ∠V to the nearest tenth of a degree.

Crazy boy [7]

Answer:

m<V = 11.2 degrees

Step-by-step explanation:

In ΔUVW, the measure of ∠W=90°, UV = 6.2 feet, and WU = 1.2 feet.

From the triangle;

UV = hypotenuse = 6.2feet

WU = opposite = 1.2feet

Required

m<V

Using the SOH CAH TOA identity

sin m<V = opp/hyp

sin m<V = WU/UV

sin m<V = 1.2/6.2

sin m<V = 0.1936

m<V = arcsin(0.1936)

m<V = 11.16

m<V = 11.2 degrees ((to the nearest tenth of a degree)

4 0

2 years ago

Read 2 more answers

15. Complete the indirect proof.

blondinia [14]

I know 17. The formula for INTERIOR angles is 180(n-2) divided by n. therefore 180(6-2) / 6 = 180 x 4 / 6 = 720 / 6 = 120.

and EXTERIOR angles is 360 divided by n, therefore 360/6 = 60.

3 0

3 years ago

Read 2 more answers

Which of the following represents a geometric series (remember what a series is as opposed to a sequence)?

juin [17]

Answer:

4 + 12 + 36 + ...

Step-by-step explanation:

4, 12, 36, ... is a geometric sequence, it has a common ratio of $r=\frac{36}{12}=\frac{12}{4}=3$

When we add the terms of a geometric sequence we get a geometric series.

4+12+36+ ... is a geometric series, it has a common ratio of $r=\frac{36}{12}=\frac{12}{4}=3$

4 + 12 + 20 + ... is not a geometric series because it has no common ratio

$\frac{20}{12}\ne \frac{12}{4}$

The second choice is correct

8 0

3 years ago

What is a reasonable estimate for the solution? O (1,-3/4) O (-3/4,1) O (-1,3/4) O (3/4,-1)

Zina [86]

Answer:

See Explanation

Step-by-step explanation:

Your question is incomplete, as the equations or graph or table(s) were not given.

However, I'll give a general way of solving this.

Take for instance, the equations are:

$y = \frac{4}{3}x - 1$

$y = \frac{2}{3}x - \frac{1}{2}$

To do this, we start by equating both equations.

$y = y$

i.e.

$\frac{4}{3}x - 1= \frac{2}{3}x - \frac{1}{2}$

Collect Like Terms

$\frac{4}{3}x - \frac{2}{3}x= 1 - \frac{1}{2}$

Take LCM

$\frac{4x- 2x}{3}= \frac{2 - 1}{2}$

$\frac{2x}{3}= \frac{1}{2}$

Cross Multiply

$2x * 2 = 3 * 1$

$4x = 3$

Make x the subject

$x = \frac{3}{4}$

Substitute 3/4 for x in $y = \frac{4}{3}x - 1$

$y = \frac{4}{3} * \frac{3}{4} - 1$

$y = 1 - 1$

$y = 0$

Hence:

$(x,y) = (\frac{3}{4},0)$

6 0

3 years ago

The mass of 5 m' of copper is 44 800 kg. Work out the density of copper.