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Leto [7]
3 years ago
9

How many different combinations of “on” and “off” are possible with 8 “lightbulbs”?

Mathematics
1 answer:
viktelen [127]3 years ago
5 0

How many different combinations of “on” and “off” are possible with 8 “light bulbs”?

Answer: The total number of combinations of "on" and "off" that are possible with 8 "light bulbs" is 2^{8}=256

Therefore, 256 different combinations of “on” and “off” are possible with 8 “light bulbs”

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The graph provided show the volume (in cubic inches) of air in a balloon as it chang
drek231 [11]

The volume of the balloon is 500 cubic inches after 20 seconds

<h3>How to determine the volume?</h3>

From the given graph, we have:

  • Time on the x-axis
  • Volume on the y-axis

Also from the graph, we have:

V(20) = 500

This means that:

The volume of the balloon is 500 cubic inches after 20 seconds

Read more about graphs at:

brainly.com/question/4025726

#SPJ1

5 0
2 years ago
Review the problem below. Determine when the Associative, Commutative, and Additive Inverse properties are used and which operat
solmaris [256]

Answer:

christopher columbus

Step-by-step explanation:

4 0
2 years ago
Cami has a part-time job that pays $13/hour and she works 35 hours every month, Her Gross pay for the month is $455. (Show your
Sholpan [36]

Answer:

Step-by-step explanation:

this is a question people will most likely not answer since we dont know how much they deduce of taxes.

8 0
2 years ago
Chris and Jeff sold 15.5 pounds of trail mix. They sold the trail mix for $3.98 per pound.
Scrat [10]

Answer:

$61.69 You take the 15.5 and take off the .5 to begin with so you start with 15 multiply it by 3.98 to get 59.7 then you take 3.98 divide it by 2 because the .5 is the same thing as 1/2 then you get 1.99 then you add it to your 59.7 to get 61.69 and thats your answer. Hope this helps :)

4 0
3 years ago
Does anyone know the the answer to the second algebra question? Will give brainiest
astraxan [27]

Answer:

\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}

\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} }  = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}

x^{3} x^{\frac{1}{3} }

Convert them, so they have a common denominator - \frac{1}{3}

\frac{3}{1}  * \frac{1}{3}=  \frac{9}{3}

\frac{9}{3} + \frac{1}{3} = \frac{10}{3}

[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]

8 0
3 years ago
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