3 years ago

How many different combinations of “on” and “off” are possible with 8 “lightbulbs”?

1 answer:

5 0

How many different combinations of “on” and “off” are possible with 8 “light bulbs”?

Answer: The total number of combinations of "on" and "off" that are possible with 8 "light bulbs" is $2^{8}=256$

Therefore, 256 different combinations of “on” and “off” are possible with 8 “light bulbs”

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DiKsa [7]

Paul surely charges 75 dollars, and then he adds 40 dollars per hours. This means that the expression for the money he asks is

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where $m$ is the amount of money and $h$ is the number of hours.

Since $h$ can be at most 8, this is the case that generates the highest money, so if we plug $h=8$ we have

$m = 75+40\cdot 8 = 75 + 320 = 395$

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Ivan

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Step-by-step explanation

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vlada-n [284]

8.4 x 10^4 hope this helps

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Mumz [18]

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$300

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1/4of $1800=$450-$150=$300

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