The correct answer is C, miles.
Answer:
118x
Step-by-step explanation: hopes this helps
For f(x) = 12/(1+x²), and subinterval width 4, you are to evaluate f(1), f(5), and f(9) and combine them according to the rule
... Integral ≈ (4/3)(f(1) + 4·f(5) + f(9)) = (4/3)(6.0000 + 4·0.4615 + 0.1463) ≈ 10.66
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Simpson's rule has you combine values of f(x) with coefficients 1, 4, 2, 4, ..., 2, 4, 1, where those values are evenly spaced at the edges of an even number of subintervals. Since we have only 3 values to combine, there are no terms that have a coefficient of 2. The entire sum is multiplied by 1/3 the subinterval width.
State which of the following ordered pairs is a function. Set A: (-1, 0), (-2, 1), (4, 3), (3, 4) Set B: (1, 4), (2, 3), (3, 2),
liubo4ka [24]
Sets A and B are both functions because they all have different x values. Set C is not a function because it repeats the x value of 2 and gives it two different y values.