All categories

2 years ago

Which equation is not a linear equation?

Mathematics

1 answer:

lubasha [3.4K]2 years ago

5 0

Answer:

a is not a linear equation

You might be interested in

Solve for x, 12y+6=6(y+1)

Vanyuwa [196]

For this case we must solve the following equation:

$12y + 6 = 6 (y + 1)$

We apply distributive property on the right side of the equation:

$12y + 6 = 6y + 6$

We subtract 6y on both sides of the equation:

$12y-6y + 6 = 6\\6y + 6 = 6$

We subtract 6 from both sides of the equation:

$6y = 6-6\\6y = 0$

Dividing by 6 on both sides of the equation:

$y = 0$

So, the result is $y = 0$

Answer:

$y = 0$

4 0

3 years ago

Qual é o coeficiente linear da funçao f(x) =2x - 1?

raketka [301]

Resposta: f ^ (- 1) (x) = (1/2) x-1/2

7 0

3 years ago

Leyla drops a penny from a height of 150 m.

gizmo_the_mogwai [7]

When the penny hits the ground, h will = 0.

So: Set h(t) = 0 = -4.9t^2 + 0t + 150 m

Then 4.9t^2 = 150, and so t^2 = sqrt(150 / 4.9) = plus or minus 5.53 sec.

We can use only the positive root, as we're measuring time.

t = 5.5 sec (answer)

8 0

3 years ago

Read 2 more answers

Use radical notation to rewrite the expression 144 1/2

andrew-mc [135]

$144^{\frac{1}{2}} = \sqrt{144}$

7 0

3 years ago

A map uses a scale of 3/4 in = 80 miles. If two buildings are 60 miles apart in real life, how far apart would they be drawn on

Alla [95]

Given:

The scale of a map is $\dfrac{3}{4}\ in=80\ miles$ .

The distance between two buildings is 60 miles.

To find:

The distance between the given building on the map.

Solution:

We have,

$\dfrac{3}{4}\ in=80\ miles$

It means, 80 miles in real life = $\dfrac{3}{4}\ in$ on the map.

1 mile in real life = $\dfrac{3}{4\times 80}\ in$ on the map.

60 mile in real life = $\dfrac{3\times 60}{4\times 80}\ in$ on the map.

= $\dfrac{180}{320}\ in$ on the map.

= $\dfrac{9}{16}\ in$ on the map.

Therefore, the buildings are $\dfrac{9}{16}\ in$ apart on the map.

7 0

3 years ago