Answer:
#include <iostream>
using namespace std;
void matrix(){
int row = 5, col = 6;
int myarr[row][col];
for (int i = 0; i < 5; i++){
for (int x = 0; x < 6; x++){
if (i == 0){
myarr[i][x] = (x+1)*(x+1);
}else if ( x == 0){
myarr[i][x] = (i+1)*(i+1)*(i+1);
} else if ( i == x){
myarr[i][x] = (i+1);
} else{
myarr[i][x] = myarr[i-1][x] + myarr[i][x-1];
}
}
}
for (int i = 0; i < 5; i++){
for (int x = 0; x < 6; x++){
cout<< myarr[i][x] << " ";
}
cout<< "\n";
}
}
int main(){
matrix();
}
Explanation:
The C++ source code defines a two-dimensional array that has a fixed row and column length. The array is a local variable of the function "matrix" and the void function is called in the main program to output the items of the array.
Your answer would be: P<span>redatory Pricing .</span>
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Answer:
Answer explained
Explanation:
From the previous question we know that while searching for n^(1/r) we don't have to look for guesses less than 0 and greater than n. Because for less than 0 it will be an imaginary number and for rth root of a non negative number can never be greater than itself. Hence lowEnough = 0 and tooHigh = n.
we need to find 5th root of 47226. The computation of root is costlier than computing power of a number. Therefore, we will look for a number whose 5th power is 47226. lowEnough = 0 and tooHigh = 47226 + 1. Question that should be asked on each step would be "Is 5th power of number < 47227?" we will stop when we find a number whose 5th power is 47226.
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The full Form of BIT is "Binary digit" which is the basic unit of information in computing . A Binary digit can be 0 or 1 . 0 represents off state & 1 represents on state .
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