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3 years ago

Subract 2.2 and 41.5

Mathematics

2 answers:

LuckyWell [14K]3 years ago

4 0

Answer:

39.3

Step-by-step explanation:

41.5 - 2.2 = 39.3

Hope that helps!

11Alexandr11 [23.1K]3 years ago

3 0

Answer:

-39.3

Step-by-step explanation:

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Calculate, to four decimal places, the first ten terms of the sequence. an = 1 +(−4/9)^n

Lemur [1.5K]

The first ten terms of the sequence $a_n=1 + (-\frac{4}{9} )^n$ is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

$a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\$

$When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\$

The first ten terms of the sequence $a_n=1 + (-\frac{4}{9} )^n$ is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

Find out more on equation at: brainly.com/question/2972832

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2 years ago

Algebra II Help??? Subtracting Fractions<br><br> (2x)/(y^2-x^2) - (x)/(y-x)

denis23 [38]

Make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
$\frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2}$ =
$\frac{2x-x(x+y)}{y^2-x^2}$ =
$\frac{2x-x^2-xy}{y^2-x^2}$

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3 years ago

Find the x-values that are solutions of the equation 5cot^2x-15=0

julia-pushkina [17]

First solve for the trig function 'cot'
$cot^2 x = \frac{15}{5} = 3$

Next take the sqrt of both sides (include plus/minus)
$cot x = \pm \sqrt{3}$

Now take reciprocal of both sides, this will change trig function to 'tan'
(cot = 1/tan)

$tan x = \pm \frac{1}{\sqrt{3}} = \pm \frac{\sqrt{3}}{3}$

Finally use the unit circle or inverse tan on your calculator to find x.
There will be 4 solutions, one for each quadrant.

$x = \frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6}$

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3 years ago

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Rom4ik [11]

<span>The definition of a perfect cube is a number that is the result of multiplying an integer by itself three times
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3 years ago

I need help with the problem

zzz [600]

I think it should be angle bisector

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3 years ago