Answer:
3x +15y +7z = 46
Step-by-step explanation:
The cross product of v = <2, 1, -3> and PQ = <-5, 1, 0> is <3, 15, 7>, the normal vector of the plane of interest. That plane contains P and Q, so the constant in the plane's equation will be ...
<3, 15, 7> · <3, 2, 1> = 46
The desired equation is ...
3x +15y +7z = 46
Answer:
R___S___T
RT=RS+ST
(17y-33) =( 9y+3)+(3y+4)
17y-33 = 12y+ 7
17y - 12y = 7+33
5y= 40
y=40/5
y= 8
RS = 9y+3 = 9(8)+3= 72+3=75
ST= 3y+4 = 3(8)+4=24+4=28
RT= 17y-33= 17(8)-33= 136-33= 103 —>
<u>Or</u><u> </u><u>;</u> RT=RS+ST =75+28= 103
<h3><u>So</u><u>;</u></h3><h3>a. <u>Ans;</u> y=8</h3>
<h3>b. <u>Ans;</u> RS= 75 , ST = 28 , RT = 103</h3>
I hope I helped you^_^