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Mathematics

2 answers:

lubasha [3.4K]2 years ago

8 0

The answer is the last option, hope this helps lol

expeople1 [14]2 years ago

6 0

Answer:

C. and D.

Step-by-step explanation:

We can cross of A. because if A. were to be correct, nothing else would be correct.

Now we know it has to be B. or C. and D.

D. has to be one of them since you can't have B. and C.

To find out if it is either B. or C. we need to think into it more. So if we had the mean of 80%, that means we need to have some scores over 75%. That would be C. since it says 75% or greater.

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Use the table. Make a scatter plot relating the distance of various cities from the metro area to the population of the cities.

Dafna11 [192]

Answer:

Option (A)

Step-by-step explanation:

From the table attached,

Independent variable 'x' is will be represented by the distance from Metro area.

Similarly, dependent variable 'y' will be on y-axis.

Scatter plot relating the distances of various cities from the metro area (x) to the population of the cities (y) will be represented by the ordered pair as (x, y).

Set of ordered pairs to be plotted,

[(1, 300), (5, 275), (10, 208), (15, 135), (20, 108)]

Therefore, graph given in Option (A) will be the answer.

4 0

2 years ago

I need to know what “x” in the angle measures

arlik [135]

X=[(x+60°)-20°]/2
x=(x+60°-20°)/2
x=(x+40°)/2
Solving for x: Multiplying both sides of the equation bu 2:
2x=2(x+40°)/2
2x=x+40°
Subtracting x both sides of the equation:
2x-x=x+40°-x
x=40°

Answer: x=40°

5 0

3 years ago

The dimensions of four rectangles are given below. Which has an area different from the area of each of the other three?

storchak [24]

To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b

The dimension of the 4 rectangles are:

a. length: 4x and width: 4

b. length: 11 and width: x

c. length: 2 and width: 8x

d. length: 16x and width: 1

The area of a rectangle is:

$Area = Length \times Width$