If X is a normally distributed random variable with mean .30 and standard deviation .06 : (draw appropriate diagrams) a) Find P(
1 answer:
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The missing choices are:
A. z-score = 92 - 83
B. z-score = (92 - 83)/5
C. z-score = 83 - 92
D. z-score = (92 - 83)/92
The expression she would write to find z-score is z-score = ⇒ B
Step-by-step explanation:
The rule of z-score is z = (x -μ)/σ, where
- x is the score
- μ is the mean
- σ is the standard deviation
The scores of an eighth-grade math test have a normal distribution
∵ The mean is 83
∴ μ = 83
∵ The standard deviation is 5
∴ σ = 5
∵ Din’s test score was 92
∴ x = 92
- Substitute all of these values in the formula of z-score
∴ z-score =
The expression she would write to find z-score is z-score =
Learn more:
You can learn more about z-score in brainly.com/question/7207785
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