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Svetradugi [14.3K]
3 years ago
15

If X is a normally distributed random variable with mean .30 and standard deviation .06 : (draw appropriate diagrams) a) Find P(

X > .25) b) P(X < .10) c) How would you describe the largest 5% of all values of X?
Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0

Answer:

0.34  x 0.38

=0.1292

Step-by-step explanation:

Hopefully this helps, if not HMU and I will try my best to get you a better answer! :)

Good luck! <3

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The drama club sold 209 evening show tickets for $18.50 each and some afternoon show tickets. They want to make $5,700 for the t
Zina [86]

Answer:

156

Step-by-step explanation:

209x18.50=3866.5

5700-3866.5=1833.5

1833.5÷11.75=156.04

3 0
2 years ago
What is the following product? (5√2-4√3)(5√2-4√3)
Galina-37 [17]

Step-by-step explanation:

(5√2-4√3)(5√2-4√3)=

(5√2-4√3)^2=(5√2)^2+(4√3)^2-2(5√2)(4√3)

=25*2+16*3-10√2*4√3

=50+48-10√2*4√3

=98-10√2*4√3 is the answer

6 0
3 years ago
PLEASE HELP! I WILL MARK AS BRAINLIEST!! I REALLY NEED SOMEONES HELP!
Andrej [43]

Since this is subtraction, everything must be turned negative in the second polynomial.

(6x^2 - 5x) - (2x^2 + 3x - 2)

6x^2 - 5x - 2x^2 - 3x - (-2)

6x^2 - 5x - 2x^2 - 3x + 2

Now, reorder the terms to make it easier.

6x^2 - 2x^2 - 5x - 3x + 2

Now, just combine like terms.

4x^2 - 5x - 3x + 2

4x^2 - 8x + 2

There’s the answer!

Please consider marking this answer as Brainliest to help me advance.

4 0
3 years ago
Lisa spends $8.65 each week on school lunches. How much money does Lisa spend on school lunches in 16 weeks? *
FrozenT [24]

Answer:

Lisa spends $138.40 on school lunches in 16 weeks.

Step-by-step explanation:

You have to multiply 8.65 by 16, since 8.65 is how much money Lisa spends each week for lunch, then you multiply by 16 since the problem calls for 16 weeks, then you get your final answer of $138.40.

3 0
2 years ago
Read 2 more answers
41°F equals how many degrees Celsius?
GrogVix [38]
<span>So we wan't to know hot to convert degrees Fahrenheit to degrees Celsius. Let's transform first from Celsius to Fahrenheit: 0 degrees Celsius is 32 degrees Fahrenhiet and 1.8 degrees Celsius is 1 degree Fahrenheit so: T(F)=1.8T(C) + 32. To transform from Celsius to Fahrenheit we need to invert the former equation: 1.8T(C)= T(F)-32. Now we divide the whole equation with 1.8 and we get: T(C)=(T(F) - 32)/1.8 and input our T(F)=41 F and we get: T(C) =(41-32)/1.8 and that is equal to: T(C)= 5 C. So the correct answer is B. 5 degrees C</span>
3 0
3 years ago
Read 2 more answers
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