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Nezavi [6.7K]
3 years ago
8

Input is also called? Dependent VariableIndependent Variable​

Mathematics
2 answers:
irga5000 [103]3 years ago
6 0

independent variable input

Setler79 [48]3 years ago
6 0
Answer: independent Variable

Explanation: An independent variable is an input, assumption, or driver that is changed in order to assess its impact on a dependent variable (the outcome). Think of the independent variable as the input and the dependent variable as the output.
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You received partial credit in th
Blababa [14]

Answer:

Expected value would be $ 0.896

Step-by-step explanation:

Given,

The price of the lottery ticket = $44800000,

Also, the probability of winning the grand prize = .000000020,

Thus, the expected value of the lottery ticket = value of the lottery ticket × probability of getting the lottery ticket

= 44800000 × .000000020

= $0.896

Note : value of lottery ticket = prize amount - cost of each ticket,

Here the cost price of a ticket is not given,

That's why we did not consider it.

5 0
3 years ago
What is the slope of the line joining (3,8) and (12,11)
olga2289 [7]
Slope formula 
\frac{y_2-y_1}{x_2-x_1}

Plug in the info given from the 2 coordinates: 
\frac{11-8=3}{12-3=9}

Simplify the slope: 
<span>\frac{3/3=1}{9/3=3}

Final answer: </span>Slope=1/3
6 0
4 years ago
Which pairs of expressions are equivalent? more than one answer
Vilka [71]

Answer:

Correct answers are

First one

Second one

Third one

Step-by-step explanation:

3x+5x=8x

3(x+4)=3x+12

a+a+b=2a+b

4 0
3 years ago
Read 2 more answers
If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
Vesna [10]

Answer:

8 units

Step-by-step explanation:

Hello!

So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that  c = \sqrt{{a}^2 + b^{2} }, where <em>c</em> is the hypotenuse and <em>a</em> and <em>b </em>are the legs of the triangle.

So, from the problem,  if <em>c </em>= 17 and <em>a </em> = 15, then, we're solving for <em>b</em>. So we'll rewrite the theorem to solve for <em>b</em>.

{c}^2 = {a}^2+{b}^2\\{c}^2-{a}^2={b}^2\\{b} = \sqrt{{c}^2-{a}^2}

Okay, so now we have isolated the theorem for <em>b. Let's </em>plug in our values for <em>c </em>and <em>a</em>.

b = \sqrt{{17}^2-{15}^2}\\b = \sqrt{289-225}\\b = \sqrt{64}\\b = 8

So, using the theorem, we found <em>b</em> = 8. To check our work, let's plug in <em>b</em> and <em>a</em> and solve for <em>c.</em>

<em />c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\<em />

So, we got our hypotenuse to equal 17 units, which is correct! So, our <em>b</em> is correct too. Awesome

7 0
3 years ago
Someone please help
shepuryov [24]

Answer:

A

Step-by-step explanation:

2 cubes horizontal,  3 cubes (down) vertical,  2 cubes horizontal.

4 0
3 years ago
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