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3 years ago

Input is also called? Dependent VariableIndependent Variable

Mathematics

2 answers:

irga5000 [103]3 years ago

6 0

independent variable input

Setler79 [48]3 years ago

6 0

Answer: independent Variable

Explanation: An independent variable is an input, assumption, or driver that is changed in order to assess its impact on a dependent variable (the outcome). Think of the independent variable as the input and the dependent variable as the output.

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Y=2x+5<br> X=5x+9 How Do you solve this solution

andreyandreev [35.5K]

Try finding what x is first from the second equation. Then plug in the answer

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3 years ago

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1. Sam won over super bouncy balls playing horseshoes at her school's game night. Later, she gave two to each of her friends. Sh

schepotkina [342]

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3 years ago

Use f’( x ) = lim With h ---> 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²

beks73 [17]

<h2>Answer:</h2>

The derivative of the function f(x) is:

$f'(x)=-2x$

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

$f(x)=5-x^2$

We have:

$f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)$

( Since,

$(a+b)^2=a^2+b^2+2ab$ )

Hence, we get:

$f(x+h)=5-x^2-h^2-2xh$

Also, by using the definition of f'(x) i.e.

$f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}$

Hence, on putting the value in the formula:

$f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x$

Hence, the derivative of the function f(x) is:

$f'(x)=-2x$

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3 years ago

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HELP<br> I also need the answer to this

ser-zykov [4K]

Hey!

To divide fractions, you have to keep, change, flip.

Keep 3 1/2(7/2)

Change ÷ to ×

Flip 2 1/4(9/4) = 4/9

Now multiply the improper fractions

$\frac{7}{2} \times \frac{4}{9} = \frac{28}{18} = 1 \frac{10}{18} = 1 \frac{5}{9}$

<em>The 1st choice matches the answer. The answer is the 1st choice.</em>

Good luck and hope this helps! :)

5 0

3 years ago

Mrs. Lane took a survey of the types of pants her students were wearing. She collected the data at the right. What percent of he

Nadya [2.5K]

Answer:

It is always important to go through the given problem first to get a concept of the requiremement. Then all the information's available from the question has to be noted down in such a manner that there would be no need to look at the question while solving.

Total number of students wearing jeans = 10

Total number of students wearing shorts = 9

Total number of students wearing capris = 2

Then the total number of students surveyed by Mrs Lane = (10 + 9 + 2)

= 21

Now percentage of students wearing shorts = (9/21) * 100

= (3/7) * 100

= 300/7

= 42.85 percent

So a total percentage of 42.85% of the students were wearing shorts.

Step-by-step explanation:

6 0

3 years ago

Input is also called? Dependent VariableIndependent Variable​

Input is also called? Dependent VariableIndependent Variable