68 is the 22nd term of the following sequence.
<u>Step-by-step explanation:</u>
- The given sequence is with the same common difference between the two consecutive number in the series thus it is said to be the Arithmetic progression ( AP).
- For finding the nth term in the AP we have a formula tn = a + (n-1) × d
- Here a is the first term , n is the number of the term to be founded and d is the common difference between the two consecutive number in the series.
- Thus here tn = 5 + ( 22 - 1 ) × 3.
- On subtracting we get tn = 5 + (21 ) × 3
- On multiplying we get tn = 5 + 63
- After adding we get tn = 68. It is the 22nd term in the given series.
If a = b then a + b = c is
2a = c
OR
2b = c
Note the equal sign. What you do to one side, you do to the other.
Isolate the variable. Divide 4 from both sides
(-52)/4 = (4m)/4
m = -52/4
m = -13
-13 is your answer for m
hope this helps
Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
