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4 years ago

Which of the following is not a way to represent the solution of the inequality 7 − 9x − (x + 12) less than or equal to 25?

Mathematics

2 answers:

Ann [662]4 years ago

6 0

Answer:

A) x greater than or equal to −3

Step-by-step explanation:

We have the following inequality:

7 − 9x − (x + 12) ≤ 25

Solving the inequation, we have:

7 − 9x − x - 12 ≤ 25

-10x ≤ 30

-x ≤ 3

x≥-3

Therefore the result is option A) x greater than or equal to −3

geniusboy [140]4 years ago

4 0

Answer:

Step-by-step explanation:

7-9x - (x+12) ≤ 25

7 - 9x - x - 12 ≤ 25

-10x - 5 ≤ 25

-10x ≤ 25 +5

x ≥ 30/-10

x ≥ -3.

So, the incorrect answer is B.

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3 years ago

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natka813 [3]

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I think i don't really know its been awhile for me.

Step-by-step explanation:

But i think you do 2 x 10 and what ever you get from that you multiply by 5 and what get from that you divide by 24.

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3 years ago

Find the simplified product b-5/2b x b^2+3b/b-5

White raven [17]

Answer:

The product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

Step-by-step explanation:

Given expression $\frac{b-5}{2b}$ and $\frac{b^2+3b}{b-5}$

We have to find the product of $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Consider the given expression $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Multiply fractions, we have,

$\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}$

$=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}$

Cancel common factor ( b - 5 )

we have, $=\frac{b^2+3b}{2b}$

Apply exponent rule,

$\:a^{b+c}=a^ba^c$

$b^2=bb$

$=bb+3b=b(b+3)$

$=\frac{b\left(b+3\right)}{2b}$

Cancel common factor b , we have,

$=\frac{b+3}{2}$

Thus, the product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

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3 years ago

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