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allsm [11]
3 years ago
5

When writing a summary about the theme you should....

Mathematics
2 answers:
vova2212 [387]3 years ago
4 0

Answer: D, All of the above

Step-by-step explanation:

pshichka [43]3 years ago
3 0
I think this would be all of the above but I’m sorry if it’s wrong. Hope this helps :-)
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Simplify: -1 | 2/3 - 4 | / 5/6
stealth61 [152]

Answer:

<h3>4</h3>

Step-by-step explanation:

- 1 | \frac{2}{3}  - 4|  \div  \frac{5}{6}  \\  - 1 | \frac{2}{3} -  \frac{4 \times 3}{1 \times 3}  |  \div  \frac{5}{6}  \\  - 1 | \frac{2 - 12}{3} |  \div  \frac{5}{6}  \\  - 1 | \frac{ - 10}{3} |  \div  \frac{5}{6}  \\  \frac{10}{3}  \div  \frac{5}{6}  \\  \frac{10}{3}  \times  \frac{6}{5}  \\  \frac{2}{1}  \times  \frac{2}{1} = 4

3 0
3 years ago
Help Me With This Show Work If You Want
puteri [66]
Use the Pythagorean therm , you know the a^2+b^2=c^2 
8 0
3 years ago
Please help I’m failing
vredina [299]

The answer is B.........

8 0
3 years ago
Read 2 more answers
Is 6 divisible by 36
andrew-mc [135]
In the terms you used, not unless you want an integer for an answer.
8 0
3 years ago
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This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,
Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Person has the flu.
  • Event B: Person got the flu shot.

The percentages associated with getting the flu are:

  • 20% of 30%(got the shot).
  • 65% of 70%(did not get the shot).

Hence:

P(A) = 0.2(0.3) + 0.65(0.7) = 0.515

The probability of both having the flu and getting the shot is:

P(A \cap B) = 0.2(0.3) = 0.06

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

7 0
2 years ago
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