The answer is 6.5t2+0.5t−5.5 , it’s simplified
It is not A or C, and D isn't specific enough (over what amount of time? is it flying up? down? It is going forward at the same height?) The most likely thing to stay consistent is the cost of fabric and it's length.
Say 1 foot of fabric is $3 (assuming there's no discount for additional feet, but math isn't that consistent with actual store sales), then 2 is $6, and 3 is $9. That is a constant rate of change.
Answer:
Answer:
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
Step-by-step explanation:
Potatoes : No Potatoes : Difference Difference (d)²
(Potatoes- No Potatoes)
29 41 -12 144
25 41 -16 256
17 37 -20 400
36 29 -7 49
41 30 11 121
25 38 -13 169
32 39 -7 49
29 10 19 361
38 29 9 81
34 55 -21 441
24 29 -5 25
27 27 0 0
<u>29 31 -2 4 </u>
<u> ∑ -64 2100 </u>
- We state our null and alternative hypotheses as
H0 : μd= 0 and Ha: μd≠0
2. The significance level alpha is set at α = 0.01
3. The test statistic under H0 is
t= d`/sd/√n
which has t distribution with n-1 degrees of freedom.
4. The critical region is t > t (0.005,12) = 3.055
5. Computations
d`= ∑d/n = -64/ 13= -4.923
sd²= ∑(di-d`)²/ n-1 = 1/n01 [ ∑di² - (∑di)²/n]
= 1/12 [2100- ( -4.923)] = 175.410
sd= √175.410 = 13.244
t = d`/sd/√n= - 4.923/13.244/√13
t= - 4.923/3.67344
t= -1.340
6. Conclusion :
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
Step-by-step explanation:
C4H6O3 + H2O => 2C2H4O2
C2H4 + 3O2 => 2CO2 + 2H2O
C4H10O + 6O2 => 4CO2 + 5H2O
