Solution
For this case we can do the following:
A) 15, 21
LCM= 105
15= 3*5
21 = 7*3
LCM= 3*5*7
b) 15,30
LCM= 30
15= 3*5
30 = 2*5
LCM= 2*3*5= 30
c) 24,72
LCM= 72
24= 2*3*4
72= 2* 2*2*3*3
LCM= 2*2*2*3*3
d) 16,42
LCM= 336
16= 2*2*4
42= 2*3*7
LCM= 2*2*3*7*4
e) 8,30
LCM=120
8= 2*4
30= 2*3*5
LCM= 2*3*4*5=120
f) 18,30
LCM=90
18= 2*3*3
90= 2*5*3*3
LCM= 2*5*3*3
g) 8,16,20
LCM= 80
8= 2*2*2
16= 2*2*2*2
20= 2*2*5
LCM= 2*2*2*2*5
No. of gallons required = csa of cuboid+area of rectangle/300
= 2(l+b)h + l*b /300
= 2(11+12)8 +11 *12 /300
=368+132/300
= 500/300
=5/3 =1.666.... =1.7
= 2 approx.
therefore 2 gallons should be used
I'm currently doing a test that includes this question, but i do believe it is C!
Answer:
x=-.5
Step-by-step explanation:
I would say 3 servings and 1/8 extra