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3 years ago

Please help appreciate it!!

Mathematics

2 answers:

murzikaleks [220]3 years ago

7 0

Answer:

I only

Step-by-step explanation:

It is the only one that passes through both.

Desmos is a great graphing calculator

Softa [21]3 years ago

5 0

Answer:

the is answer is neither

Step-by-step explanation:

i also used desmos and i got neither.

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a region's average movie theater ticket price in 2007 was $6.72. For 2017, it was estimated to be $8.81. Find the percent of inc

Alex73 [517]

Answer:

31.1011905%

Step-by-step explanation:

Take the new price and subtract the original price

8.81 - 6.72

2.09

Divide by the original price

2.09/6.72

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Change to percent form

31.1011905%

3 0

2 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

6 0

2 years ago

What is the slope of the line shown below? answer quick pls

AVprozaik [17]

A. 1the answer is A. 1

8 0

3 years ago

What’s (2^2+8)x7 please help

Ivenika [448]

Answer:

Step-by-step explanation:

2^2=4

4+8=12

12*7=84

3 0

2 years ago

Evaluate and answer in standard form:<br><br>4^2/3^2

Semenov [28]

the answer is : 1.7777

6 0

3 years ago