Solve the inequality and graph its solution... 3+v≤-9
1 answer:
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A,B,C,D i.e. all statements are true!
<u>Step-by-step explanation:</u>
According to question, Lynn works as a part-time vendor selling necklaces for $15 each and bangles for $10 each. She needs to earn a minimum of $300 per week to cover her expenses. The inequality for above scenario will be :
where, x is number of necklaces & y is number of bangles.
A.
Lynn will meet her goal if she sells 12 bangles and 12 necklaces. i.e. x=12 and y=12 , putting values inequality : which follows inequality . True statement!
B.
Lynn will meet her goal if she sells 20 bangles and 6 necklaces.
putting values inequality : which follows inequality . True statement!
C.
Lynn will meet her goal if she sells 6 bangles and 12 necklaces. putting values inequality : , which follows inequality . True statement!
D.
Lynn will meet her goal if she sells 2 bangles and 18 necklaces.putting values inequality : , which follows inequality . True statement!
Answer:
Check the explanation
Step-by-step explanation:
Let and
be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume having with mean
and
having mean
Also we have given the variance is constant
A)
We can test hypothesis as
For this problem
Test statistic is
Where
We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.