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3 years ago

What is the area of 1 section of this circle?

Mathematics

1 answer:

Kruka [31]3 years ago

4 0

Answer:

144

Step-by-step explanation:

you take the area of the circle,,,

then you divide it by pi

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A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of

Troyanec [42]

Answer:

The ordinate of B exceeds the ordinate of A by 7

Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

$m=\frac{y2-y1}{x2-x1}$

$m=2$

$2=\frac{y2-y1}{x2-x1}$ -----> equation A

$x2=x1+3.5$ ----> equation B

substitute equation B in equation A

$2=\frac{y2-y1}{x1+3.5-x1}$

$2=\frac{y2-y1}{3.5}$

$7=y2-y1$

$y2=y1+7$

therefore

The ordinate of B exceeds the ordinate of A by 7

6 0

3 years ago

Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu

dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

$d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\$ Substituting the values

$d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\$

So the total distance travelled is 1031 feet.

4 0

3 years ago