x-2 is a factor so x = 2 is a root of f(x)
This is because f(x) = (x-2)*g(x) for some polynomial g(x). We don't have to worry about what g(x) is equal to as it doesn't affect the status of the root we're after.
So,
f(x) = 0
(x-2)*g(x) = 0
x-2 = 0 or g(x) = 0
x = 2 or g(x) = 0
This shows how the factor x-2 leads to the root x = 2
Therefore, f(2) = 0
Answer: Choice D
Answer:
2 ( x+3) (x+1)
Step-by-step explanation:
2x^2+8x+6
Factor out a 2
2(x^2 +4x+3)
Factor in side the parentheses
What multiply to 3 and adds to 4 (3(1=3 3+1 =4)
2 ( x+3) (x+1)
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