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serg [7]
2 years ago
6

Will someone please help me with this??

Mathematics
1 answer:
ehidna [41]2 years ago
7 0

\huge \mathfrak { \green{A} \pink{n} \orange{s}{w}{\blue{e}}{ \gray{r}}} \\  \\  \:  \:  \:  \implies \:  \mathbb{C.  - 3}

The leading term is the term containing the highest power of the variable: the term with the highest degree. The leading coefficient is the coefficient of the leading term.

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Factorize this expression completely <br>using (a-b)² formula<br>3a²- 36a + 108​
Novosadov [1.4K]

Answer:

3a^2 - 36a + 108  = (\sqrt{3}a - 6\sqrt{3} )^2

Step-by-step explanation:

3a^2 = (\sqrt{3} a)^2\\108 = 9 \times 4 \times 3= 3^2 \times 2^2 \times 3 = (3\times2 \sqrt{3} )^2 = (6\sqrt{3})^2

so, a = \sqrt{3}  a \ , \ b = 6\sqrt{3} \\\\(a - b)^2 = a^2 -2ab + b^2\\\\-36a = -2ab\\\\-36a = -2 \times \sqrt{3} a \times 6\sqrt{3}

Therefore ,

3a^2 - 36a + 108 = (\sqrt{3}a )^2 - 2(\sqrt{3}a \times 6\sqrt{3} ) + (6\sqrt{3} )^2  = (\sqrt{3}a - 6\sqrt{3} )^2

6 0
3 years ago
Does anyone wanna help ya girl out?? I’ll give brainliest for best answer (it’ll go who answers first, and how helpful the answe
ludmilkaskok [199]

Answer: 1, 2, and 4

Step-by-step explanation:

3 0
3 years ago
According to the graph, how far did the object move between the second and third seconds?
Setler79 [48]

Answer:

Your answer would be B

Step-by-step explanation:

This is because in between the 2nd and 3rd seconds, there is a 2 unit space so that is how far the object moved in between these seconds,

Hope this helps you out!! Have a good day:))

7 0
2 years ago
Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En
Sergio [31]

Answer:

\bold{cot(t) =\dfrac{12}{5}}

Step-by-step explanation:

Given that:

Cosec (t) = -\frac{13}5

for \pi < t < \frac{3 \pi}2

That means, angle t is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

cosec^2\theta -cot^2\theta =1

here, \theta =t

So, cosec^2t-cot^2t=1

\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}

But, angle t is in 3rd quadrant, so value of

\bold{cot(t) =\dfrac{12}{5}}

4 0
3 years ago
Help please!!!! :)))
miv72 [106K]

Answer:

c = 2 , d = 3

Step-by-step explanation:

(2y^3)(9y^3) = 18y^6

4 0
3 years ago
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