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1 year ago

Will someone please help me with this??

Mathematics

1 answer:

ehidna [41]1 year ago

7 0

$\huge \mathfrak { \green{A} \pink{n} \orange{s}{w}{\blue{e}}{ \gray{r}}} \\ \\ \: \: \: \implies \: \mathbb{C. - 3}$

The leading term is the term containing the highest power of the variable: the term with the highest degree. The leading coefficient is the coefficient of the leading term.

You might be interested in

The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili

Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that $\mu = 74, \sigma = 15$

Question a:

Sample of 36 means that $n = 36, s = \frac{15}{\sqrt{36}} = 2.5$

This probability is 1 subtracted by the pvalue of Z when X = 78. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{78 - 74}{2.5}$

$Z = 1.6$

$Z = 1.6$ has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that $n = 150, s = \frac{15}{\sqrt{150}} = 1.2247$

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

$Z = \frac{X - \mu}{s}$

$Z = \frac{77 - 74}{1.2274}$

$Z = 2.45$

$Z = 2.45$ has a pvalue of 0.9929

X = 71

$Z = \frac{X - \mu}{s}$

$Z = \frac{71 - 74}{1.2274}$

$Z = -2.45$

$Z = -2.45$ has a pvalue of 0.0071

0.9929 - 0.0071 = 0.9858

0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c. A random sample of size 219 yielding a sample mean of less than 74.2

Sample size of 219 means that $n = 219, s = \frac{15}{\sqrt{219}} = 1.0136$

This probability is the pvalue of Z when X = 74.2. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{74.2 - 74}{1.0136}$

$Z = 0.2$

$Z = 0.2$ has a pvalue of 0.5793

0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

5 0

2 years ago

How many servings in 3/4 of a cookie when each serving is 1/2 cookie

pishuonlain [190]

1 1/2 servings are in 3/4 bc 2/4= 1/2 and theres 1/2 a cookie left and if u take half of that it gets to 3/4

3 0

2 years ago

Serhud [2]

Answer: c

Step-by-step explanation:

5 0

2 years ago

You drive 75 miles and use 3 gallons of gas, at the same ratio, how may miles can you drive with 12 gallons of gas?

umka2103 [35]

When you say "at the same ratio", you mean that you consume the same amount of gas for the same amount of miles.

We know that everytime you drive 75 miles, you use 3 gallons of gas.

Since 12 gallons of gas is four times 3 gallons of gas, if the ratio remains the same, you can drive four times the distance:

You drive 75 miles, and use 3 gallons.

You drive 75 more miles (so you are at $75+75 = 150$ miles) and use 3 more gallons, so you use $3+3 = 6$ gallons.

You drive 75 more miles (so you are at $150+75 = 225$ miles) and use 3 more gallons, so you use $6+3 = 9$ gallons.

You drive 75 more miles (so you are at $225+75 = 300$ miles) and use 3 more gallons, so you use $9+3 = 12$ gallons, and you're done.

4 0

2 years ago

Find xy if x + y=3, x^2 + y^2 = 5

Vesna [10]

Answer:

mark me

Step-by-step explanation:

x+y=3

x=3-y

putting the value of x

in this

x²+y²=5

(3-y) ²+y²=5

9-6y+y²+y²=5

2y²-6y+9-5=0

2y²-6y+4=0

2y²-4y-2y+4=0

2y(y-2)-2(y-2)=0

(2y-2) (y-2) =0

2y-2=0 or y-2=0

y=1 or y=2

so x=2 or 1

so x×y=2×1 or 1×2=2

I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST

8 0

2 years ago