Answer:
Answer is D
Step-by-step explanation:
Answer:
Given that:
and 
if a , a+ commutator, it obeys 
First find:
= 
Now;
=
therefore, which implies the operators a and a+ are commutators.
<h3>2
Answers: Choice B, Choice C</h3>
The rule we use here is 
If the font size is too small, then it says (a^b)/(a^c) = a^(b-c)
We subtract the exponents when dividing exponentials like this. The bases must be the same.
So this means the exponents 13 and 3 subtract to get 13-3 = 10
We either have an exponent of "13-3" or an exponent of "10" as an equivalent expression. The base stays at 2 the entire time.
<span>If set X is made up of the possible ways five students, represented by A, B, C, D, and E, can be formed into groups of three, then the set X consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE, BCD, BCE, BDE, CDE} (note that triple ABC is the same as triple ACB, or BCA, or BAC, or CAB, or CBA). The set X totally contains 10 elements (triples). The first statement is true.
</span>
<span>If set
Y is made up of the possible ways five students can be formed into
groups of three if student A must be in all possible groups, then </span><span>the set Y consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE} and contains 6 elements. The second statement is also true.
</span>
<span>If person E must be in each group, then there can be only one group is false statement, because you can see from the set X that triples which contains E are 6.
</span>
<span>There are three ways to form a group if persons A and C must be in it. This statement is true and these groups are ABC, ACD, ACE.</span>
