Answer:
176.625 sq.ft, 4.8 sq.ft
Step-by-step explanation:
Area of circle=πr^2 or πd^2/4
11. Given,
d=15 ft
Now,
Area=πd^2/4
3.14*15^2/4
176.625 ft^2
Therefore, the area approximation is 176.6 sq.ft
12.
Given,
d=3.5 ft
Now,
Area= πd^2/8
3.14*3.5^2/8
4.8 sq.ft
I got the answer by dividing the area of circle by 2 as semicircle is half of circle.
Answer:
-2x-10
Step-by-step explanation:
just distribute the -2 :)
Answer:
The volume is 2140.98 inches³
Step-by-step explanation
The basketballs are spherical, and it is known that the volume of a sphere is

Where V is the volume of the ball and r is its radius
They tell us that the ball measures 8.8 inches wide. This means that its diameter is 8.8 inches.
It is known that the radius of a sphere is equal to half its diameter.
Therefore, the radius r of the ball is:

r = 4.4 inches.
Then, they tell us to consider that the walls of the ball are infinitely thin, which means that we should not take into account their thickness in the calculation of the volume.
We already have all the data we need, now we proceed to calculate the volume.

Where V is the volume of only one of the balls
The volume of the six balls is V = 6 * 356.83 = 2140.98 inches³
Finally the volume is 2140.98 inches³
2/7 cup of flour
Simply multiply 2/3 by 3/7 to get
the answer. To multiply 2 fractions together, you multiply the
numerators together and then multiply the denominator together.
2/3 x 3/7 = 6/21
But 6/21 can be expressed in a simpler fashion. Notice that both 6 and
21 can be evenly divided by 3. So divide both the numerator and
denominator by 3
(6/3)/(21/3) = (2)/(7) = 2/7
Answer:
Step-by-step explanation:
The zeros of the function can be found by factoring. Since this has already been started with completing the square, we will just pick up from where it was left and finish factoring. Set the quadratic equal to 0 first.
then move over the 9:
"undo" the squaring by square rooting both sides to get
x - 8 = ±3. And then add over the 8 to get the solutions
x = 8 + 3 and x = 8 - 3. The solutions, then, are
x = 5 and x = 11