Answer:
41.15
Step-by-step explanation:
41.15
Suppose two dice are tossed and the numbers on the upper faces are observed. let s denote the set of all possible pairs that can be observed.
Answer: If two dice are tossed, there are
possible outcomes.The possible pairs that can be observed are given in a set denoted by s below:
![\left[\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccccc%7D%281%2C1%29%26%281%2C2%29%26%281%2C3%29%26%281%2C4%29%26%281%2C5%29%26%281%2C6%29%5C%5C%282%2C1%29%26%282%2C2%29%26%282%2C3%29%26%282%2C4%29%26%282%2C5%29%26%282%2C6%29%5C%5C%283%2C1%29%26%283%2C2%29%26%283%2C3%29%26%283%2C4%29%26%283%2C5%29%26%283%2C6%29%5C%5C%284%2C1%29%26%284%2C2%29%26%284%2C3%29%26%284%2C4%29%26%284%2C5%29%26%284%2C6%29%5C%5C%285%2C1%29%26%285%2C2%29%26%285%2C3%29%26%285%2C4%29%26%285%2C5%29%26%285%2C6%29%5C%5C%286%2C1%29%26%286%2C2%29%26%286%2C3%29%26%286%2C4%29%26%286%2C5%29%26%286%2C6%29%5Cend%7Barray%7D%5Cright%5D)
Answer:
40%
Step-by-step explanation:
The answer is D.
You cannot factorise it as there are two different terms being squared with the middle term containing both. Also, if you expand any of the brackets in the questions you will not get the original equation so non of them are right so it has to be D. :)
Answer:

Step-by-step explanation: