A side of a square is 10 cm longer than the side of an equilateral triangle. The perimeter of the square is 3 times the perimete
r of the triangle. Select the equation that represents the scenario when x represents the side of the triangle.
2 answers:
Answer:
Let the side of the equilateral triangle = x
so the side of the square = x+10
The perimeter of the triangle = 3x
and the perimeter of the square = 4(x+10)
condition : the perimeter of the square is 3 times the perimeter of the triangle.
so, 4(x+10) = 3*(3x)
Step-by-step explanation:
Here's the solution :
- Side of the equilateral triangle = x
perimeter of equilateral triangle = 3 × x = 3x
perimeter of square = 4 × (x + 10)
now, according to above statement :
permission (square) = 3 × perimeter (triangle)
that is :
therefore, side of triangle = 8 cm
- perimeter (triangle) = 8 × 3 = 24 cm
- side of square = 8 + 10 = 18 cm
- perimeter of square= 18 × 4 = 72 xm
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Answer:
c/8
Step-by-step explanation:
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This can be simplified using the radical properties as below
![\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\](https://tex.z-dn.net/?f=%20%5C%5C%5C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20%20%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20)
Now using exponent properties we can write
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The answer is 375..........
A. 108
B. 72
C. 36
D. 144
M. 63
N. 135
P. 63
R. ?
S. 50
T. ?
I apologize I couldn't see very well where r or t was :(