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ELEN [110]
3 years ago
7

Uh im not good at algebra sooooooooooooooooooooooooooooooooooooooo help.

Mathematics
2 answers:
serious [3.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

392 i believe

Vladimir79 [104]3 years ago
5 0
I'm not good either but I think it's 616. I'm not really sure
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Factor the expression 3x^2-15x
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Factor out 3x
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Help how can I Write the given standard equation of the quadratic in intercept form
olya-2409 [2.1K]

Answer:

f(x) = (x - 10) (x + 10)

Step-by-step explanation:

The equation looks like the difference of squares so 5 and 20 are out

-10 x -10 = 100

-10 x 10 = - 100

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2 years ago
Help me please I need to do my unit testtt
Luda [366]

Answer:

B.

Step-by-step explanation:

Although the numbers given are negative, we can see that by the lines surrounding them, it is asking for their absolute value. Since absolute values are always positive, the correct answer would be B.

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3 years ago
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6 0
3 years ago
Read 2 more answers
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

5 0
3 years ago
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