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fiasKO [112]
3 years ago
8

I can't solve this I need help??? ​

Mathematics
2 answers:
vredina [299]3 years ago
5 0
Picture or questions?
Semenov [28]3 years ago
3 0

Answer:

Yes.

Step-by-step explanation:

THERE IS NO QUESTION

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AnnZ [28]
Find the mean and median of what,
4 0
3 years ago
When z is divided by 6, the remainder is 4. What is the remain-der when z is divided by 2 ?
Aleksandr [31]

Answer:

12

Step-by-step explanation:

So first, when z is divded by 6 we get 4 left.

So an example for z could be 24.

(24 / 6 = 4)

When z is divded by 2, it would be 12

24 / 2 = 12

(I hope this helps and that you have a nice day!)

4 0
3 years ago
What is the scale factor?
fgiga [73]

Answer:

2

Step-by-step explanation:

Basically you don't need to find x to know the scale factor ,

but I did.So you see that multiple 3 by 2 you will get 6

(MN) and the same will happen with 5.5 and NO (which is 11 btw).

so you can write 2:1

5 0
3 years ago
Or a very large set of data the measured mean is found to be 288.6 with a standard deviation of 21.2. assuming the data to be no
SashulF [63]

The 68-95-99.7 rule tells us 68% of the probability is between -1 standard deviation and +1 standard deviation from the mean. So we expect 75% corresponds to slightly more than 1 standard deviation.

Usually the unit normal tables don't report the area between -σ and σ but instead a cumulative probability, the area between -∞ and σ. 75% corresponds to 37.5% in each half so a cumulative probability of 50%+37.5%=87.5%. We look that up in the normal table and get σ=1.15.

So we expect 75% of normally distributed data to fall within μ-1.15σ and μ+1.15σ

That's 288.6 - 1.15(21.2) to 288.6 + 1.15(21.2)

Answer: 264.22 to 312.98


8 0
3 years ago
A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The sec
DochEvi [55]

The statements that are true about the intervals of the continuous function are Options 2, 4  and 5

  • f(x) ≤ 0 over the interval [0, 2].
  • f(x) > 0 over the interval (–2, 0).
  • f(x) ≥ 0 over the interval [2, ).

<h3>What is the statement about?</h3>

Looking at the values given, the intervals which satisfies the condition are known to be:

f(x)<=0 over the interval [0,2]

f(x)>0 over the interval (-2,0)

f(x)>=0 over the interval [2,∞)

Because:

Since the table with x  and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .

Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)

Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]

When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)

When you look at the interval (-2,0) , the f(x)  is positive and as such, f(x)>0 over the interval (-2,0)

Looking at the interval  [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)

Therefore, Option 2, 4 and 5 are correct.

Learn more about interval from

brainly.com/question/14454639

#SPJ1

6 0
2 years ago
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