Question

Need help ASAP questions in the pics i have sent

Answer 1

Answer:

Step-by-step explanation:

Picture 1

In right triangle ABC,

Side AB is the opposite side of angle C.

Picture 2

In triangle MKL,

tan(∠M) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

             = $\frac{KL}{KM}$

             = $\frac{15}{8}$

Option (1) is the answer.

Picture 3

In ΔXYZ,

sin(∠Z) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

            = $\frac{XY}{XZ}$

For the length of XY we will apply Pythagoras theorem in ΔXYZ,

XZ² = XY² + YZ²

XY² = XZ² - YZ²

      = (40)² - (32)²

XY = √576

     = 24

sin(Z) = $\frac{24}{40}$

sin(Z) = $\frac{3}{5}$

Picture 4

In right triangle DEF,

Cos(D) = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

           = $\frac{EF}{DF}$

           = $\frac{75}{72}$

           = $\frac{25}{24}$

Picture 5

In ΔABC,

tan(63°) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

tan(63°) = $\frac{BC}{AB}$

AB = $\frac{BC}{\text{tan}(63)}$

AB = $\frac{8}{\text{tan}(63)}$

AB = 4.0762 ≈ 4 m

Option (3) will be the answer.